Solving System of Equations Homework: Trig & mv^2/L

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REVIANNA
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Homework Statement


this is actually one of the physics problems and I have boiled down the numerical to two equations.
But I have trouble manipulating equations

Homework Equations



Tsin(theta)=Fcos(theta)-mg
and
Tcos(theta)=(mv^2/Lcos(theta))-Fsin(theta)

F and T are the two unknowns

The Attempt at a Solution



I brought the terms involving m to one side and the trig functions to the other
and tried to add the the equations . But it only gets more complicated as in one eq F has a coefficient of cos(theta)+sin(theta) and in the other cos(theta)-sin(theta).same goes for coefficients of T in both equations.
 
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The form is like:
$$T\sin\theta-F\cos\theta=...$$
$$T\cos\theta+F\sin\theta=...$$
Multiplying the both ##\sin\theta## and ##\cos\theta##, and the other way around, which may help.
 
tommyxu3 said:
the other way around,
I did not understand this
 
F(cos(θ))^2 sin(θ) +Tsin^2(θ) cos(θ)
F sin^2(θ) cos(θ) -T cos^2(θ) sin(θ)

what should I do?
 
$$T\sin\theta-F\cos\theta=...(1)$$
$$T\cos\theta+F\sin\theta=...(2)$$
What I meant are ##(1)\cdot\sin\theta+(2)\cdot\cos\theta## and ##(1)\cdot\cos\theta-(2)\cdot\sin\theta.## Can you get anything from them?
 
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It worked !
How did you think about it?
And THanks
 
REVIANNA said:
I did not understand this
tommyxu3 said:
The form is like:
$$T\sin\theta-F\cos\theta=...$$
$$T\cos\theta+F\sin\theta=...$$
Multiplying the both ##\sin\theta## and ##\cos\theta##, and the other way around, which may help.
I hope that tommyxu3 did not literally mean what he wrote.

The form he gave was good.
Here's what to do from that point.

Multiply the first equation by ##\ \sin(\theta)\ ## and the second equation by ##\ \cos(\theta) \ ##, then add the equations to eliminate F . It's essentially the method of elimination. Then solve for T .
...
 
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REVIANNA said:

Homework Statement


this is actually one of the physics problems and I have boiled down the numerical to two equations.
But I have trouble manipulating equations

Homework Equations



Tsin(theta)=Fcos(theta)-mg
and
Tcos(theta)=(mv^2/Lcos(theta))-Fsin(theta)

F and T are the two unknowns

The Attempt at a Solution



I brought the terms involving m to one side and the trig functions to the other
and tried to add the the equations . But it only gets more complicated as in one eq F has a coefficient of cos(theta)+sin(theta) and in the other cos(theta)-sin(theta).same goes for coefficients of T in both equations.

It is easier if you simplify the symbolics: let ##s = \sin(\theta), c = \cos(\theta), A = mg, B = \frac{mv^2}{L} \cos(\theta)##. Then your equations read as
[tex]sT = cF - A\\<br /> cT = -sF + B[/tex]
or
[tex]\begin{array}{rcl}<br /> cF - sT &=& A\\<br /> sF + cT &=& B<br /> \end{array}[/tex]
If you know about matrices and matrix inverion you can write down the solution immediately, because in matrix form the system reads as
[tex]\pmatrix{c & s \\-s & c} \pmatrix{F\\T} = \pmatrix{A\\B}[/tex]
A crucial simplification is that ##c^2 + s^2 = 1##, because these constants are the cosine and sine of the same angle.
 
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