Solving System of Equations Homework: Trig & mv^2/L

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Homework Help Overview

The discussion revolves around a physics problem involving two equations related to forces and trigonometric functions. The original poster attempts to manipulate these equations to solve for two unknowns, F and T, but encounters difficulties in simplifying and combining them effectively.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for manipulating the equations, including suggestions to multiply by trigonometric functions and to use elimination methods. Some express confusion about the proposed approaches and seek clarification.

Discussion Status

There appears to be a productive exchange of ideas, with some participants offering guidance on how to proceed with the equations. However, not all participants fully understand the suggestions, indicating a mix of comprehension levels within the discussion.

Contextual Notes

Participants mention the need to simplify the equations and consider the implications of trigonometric identities, while also noting the complexity introduced by the coefficients of the variables involved.

REVIANNA
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Homework Statement


this is actually one of the physics problems and I have boiled down the numerical to two equations.
But I have trouble manipulating equations

Homework Equations



Tsin(theta)=Fcos(theta)-mg
and
Tcos(theta)=(mv^2/Lcos(theta))-Fsin(theta)

F and T are the two unknowns

The Attempt at a Solution



I brought the terms involving m to one side and the trig functions to the other
and tried to add the the equations . But it only gets more complicated as in one eq F has a coefficient of cos(theta)+sin(theta) and in the other cos(theta)-sin(theta).same goes for coefficients of T in both equations.
 
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The form is like:
$$T\sin\theta-F\cos\theta=...$$
$$T\cos\theta+F\sin\theta=...$$
Multiplying the both ##\sin\theta## and ##\cos\theta##, and the other way around, which may help.
 
tommyxu3 said:
the other way around,
I did not understand this
 
F(cos(θ))^2 sin(θ) +Tsin^2(θ) cos(θ)
F sin^2(θ) cos(θ) -T cos^2(θ) sin(θ)

what should I do?
 
$$T\sin\theta-F\cos\theta=...(1)$$
$$T\cos\theta+F\sin\theta=...(2)$$
What I meant are ##(1)\cdot\sin\theta+(2)\cdot\cos\theta## and ##(1)\cdot\cos\theta-(2)\cdot\sin\theta.## Can you get anything from them?
 
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It worked !
How did you think about it?
And THanks
 
REVIANNA said:
I did not understand this
tommyxu3 said:
The form is like:
$$T\sin\theta-F\cos\theta=...$$
$$T\cos\theta+F\sin\theta=...$$
Multiplying the both ##\sin\theta## and ##\cos\theta##, and the other way around, which may help.
I hope that tommyxu3 did not literally mean what he wrote.

The form he gave was good.
Here's what to do from that point.

Multiply the first equation by ##\ \sin(\theta)\ ## and the second equation by ##\ \cos(\theta) \ ##, then add the equations to eliminate F . It's essentially the method of elimination. Then solve for T .
...
 
Last edited:
REVIANNA said:

Homework Statement


this is actually one of the physics problems and I have boiled down the numerical to two equations.
But I have trouble manipulating equations

Homework Equations



Tsin(theta)=Fcos(theta)-mg
and
Tcos(theta)=(mv^2/Lcos(theta))-Fsin(theta)

F and T are the two unknowns

The Attempt at a Solution



I brought the terms involving m to one side and the trig functions to the other
and tried to add the the equations . But it only gets more complicated as in one eq F has a coefficient of cos(theta)+sin(theta) and in the other cos(theta)-sin(theta).same goes for coefficients of T in both equations.

It is easier if you simplify the symbolics: let ##s = \sin(\theta), c = \cos(\theta), A = mg, B = \frac{mv^2}{L} \cos(\theta)##. Then your equations read as
[tex]sT = cF - A\\<br /> cT = -sF + B[/tex]
or
[tex]\begin{array}{rcl}<br /> cF - sT &=& A\\<br /> sF + cT &=& B<br /> \end{array}[/tex]
If you know about matrices and matrix inverion you can write down the solution immediately, because in matrix form the system reads as
[tex]\pmatrix{c & s \\-s & c} \pmatrix{F\\T} = \pmatrix{A\\B}[/tex]
A crucial simplification is that ##c^2 + s^2 = 1##, because these constants are the cosine and sine of the same angle.
 
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