Solving Tension in Rope for 26kg Pack Hanging Between Trees

  • Thread starter Thread starter fubag
  • Start date Start date
  • Tags Tags
    Rope Tension
Click For Summary

Homework Help Overview

The problem involves determining the tension in two ropes supporting a 26kg pack suspended between two trees, with the ropes at different angles. The subject area relates to forces in equilibrium and vector components.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equations of equilibrium for the forces acting on the pack and question the sufficiency of the provided information. There is an exploration of how to incorporate the angles into the equations for tension.

Discussion Status

Some participants have provided guidance on manipulating the equations to express one tension in terms of the other. Multiple interpretations of the problem setup are being explored, particularly regarding the angles and their application in the equations.

Contextual Notes

There is a noted lack of information regarding the angles initially, which has been partially addressed by the original poster in a follow-up post. The discussion reflects on the need for clarity in the problem setup to proceed effectively.

fubag
Messages
105
Reaction score
0
A camper hangs a 26kg pack between two trees, using separate pieces of rope of different lengths. What is the tension in each rope?

I understand:

x = T1cosx - T2cox = 0

y = T1sinx + T2sinx + mg = 0.

How can I got about solving for T1, and T2?


Thanks!
 
Physics news on Phys.org
There isn't sufficient information to solve this... from the given description. You have 3 unknowns and 2 equations. Do you have additional information to find the angle?
 
im sorry

I forgot to mention the anglesOne of the angles is 71 degrees, and the other is 28 degrees.

According to my equation, T2 uses the 71 degrees angle, while T1 uses the 28 degrees angle.

This what I have so far:

T1(sin28 + cos 28) + T2(sin71 - cos71) - mg = 0.What do I do next?
 
Don't just add the two equations you have from post #1. Use the first one to solve for T1 in terms of T2, then plug that into the second equation.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
9K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
46
Views
7K
Replies
5
Views
8K
Replies
15
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K