Solving the 411nm Wavelength Emission from Hydrogen

[adream]

Homework Statement

Light of wavelength 411 nm is emitted from a hydrogen discharge. What transition produces this emission?

a. k = 5 to n =1
b. k = 4.5 to n = 2
c. k = 2 to n = 6
d. k = 2 to n = 3
e. k = 6 to n = 2

Homework Equations

R = (1/n^2 - 1/k^2)

The Attempt at a Solution

I'm not really sure how to solve it. But I'm sure its not a, b, or e. Because n to be bigger then k to make it positive. THat left me with c and d. Someone please hint me how to do this.

 

[kuruman]

Just plug in the choices for k and n pairs in the formula and see which one gives you the right wavelength.

 

[adream]

totally confused. >< can someone explain it to me.

 

[kuruman]

You posted an equation (not exactly right) which you got it from somewhere, probably a textbook. Start from there. You can also look in

http://en.wikipedia.org/wiki/Rydberg_formula