Solving the 411nm Wavelength Emission from Hydrogen

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Homework Help Overview

The problem involves determining the electronic transition in a hydrogen atom that corresponds to the emission of light at a wavelength of 411 nm. The context is rooted in atomic physics and the behavior of hydrogen emissions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to eliminate options based on their understanding of the relationship between the principal quantum numbers. Some participants suggest directly substituting the values into the provided formula to find the correct transition.

Discussion Status

The discussion is ongoing, with participants expressing confusion and seeking clarification on the application of the Rydberg formula. Some guidance has been offered regarding the use of the formula, but no consensus has been reached on the correct transition.

Contextual Notes

There is a mention of uncertainty regarding the correct application of the formula, and the original poster expresses doubt about certain options based on their reasoning about the quantum numbers.

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Homework Statement



Light of wavelength 411 nm is emitted from a hydrogen discharge. What transition produces this emission?

a. k = 5 to n =1
b. k = 4.5 to n = 2
c. k = 2 to n = 6
d. k = 2 to n = 3
e. k = 6 to n = 2

Homework Equations



R = (1/n^2 - 1/k^2)

The Attempt at a Solution



I'm not really sure how to solve it. But I'm sure its not a, b, or e. Because n to be bigger then k to make it positive. THat left me with c and d. Someone please hint me how to do this.
 
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Just plug in the choices for k and n pairs in the formula and see which one gives you the right wavelength.
 
totally confused. >< can someone explain it to me.
 

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