Solving the Equation ##10ax+bx=22x##

  • Thread starter Thread starter chwala
  • Start date Start date
AI Thread Summary
The discussion focuses on solving the equation 10ax + bx = 22x, leading to the conclusion that 10a + b = 22. Participants emphasize the importance of validating one's own work and developing self-checking skills for effective test-taking. There is a call for clearer communication in seeking help, as assumptions about others' understanding can lead to confusion. The need for explicit questions when asking for assistance is highlighted. Overall, the conversation stresses the value of self-reliance in problem-solving and clear communication in collaborative learning.
chwala
Gold Member
Messages
2,827
Reaction score
415
Homework Statement
See attached
Relevant Equations
simultaneous equations
1632307697683.png


I got ##22##,
i.e ##100ax+10bx+10ay+by=220x+22y##
→## 10ax+bx=22x##
→##10ay+by=22y##
→##10a+b=22##
 
Physics news on Phys.org
Do you not know how to check your own work? You should not have to ask whether you got the right answer, you should be able to validate it on your own. Learning to do this is an essential skill for test-taking.
 
phinds said:
Do you not know how to check your own work? You should not have to ask whether you got the right answer, you should be able to validate it on your own. Learning to do this is an essential skill for test-taking.
Agreed the reason why i post is to seek alternative ways of doing it...
 
chwala said:
Agreed the reason why i post is to seek alternative ways of doing it...
And you expected us to be mind readers and KNOW that that was why you posted? Please be more explicit in what you are asking.
 
  • Haha
  • Like
Likes chwala and Delta2
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top