Solving the Equation ##10ax+bx=22x##

  • Thread starter Thread starter chwala
  • Start date Start date
AI Thread Summary
The discussion focuses on solving the equation 10ax + bx = 22x, leading to the conclusion that 10a + b = 22. Participants emphasize the importance of validating one's own work and developing self-checking skills for effective test-taking. There is a call for clearer communication in seeking help, as assumptions about others' understanding can lead to confusion. The need for explicit questions when asking for assistance is highlighted. Overall, the conversation stresses the value of self-reliance in problem-solving and clear communication in collaborative learning.
chwala
Gold Member
Messages
2,827
Reaction score
415
Homework Statement
See attached
Relevant Equations
simultaneous equations
1632307697683.png


I got ##22##,
i.e ##100ax+10bx+10ay+by=220x+22y##
→## 10ax+bx=22x##
→##10ay+by=22y##
→##10a+b=22##
 
Physics news on Phys.org
Do you not know how to check your own work? You should not have to ask whether you got the right answer, you should be able to validate it on your own. Learning to do this is an essential skill for test-taking.
 
phinds said:
Do you not know how to check your own work? You should not have to ask whether you got the right answer, you should be able to validate it on your own. Learning to do this is an essential skill for test-taking.
Agreed the reason why i post is to seek alternative ways of doing it...
 
chwala said:
Agreed the reason why i post is to seek alternative ways of doing it...
And you expected us to be mind readers and KNOW that that was why you posted? Please be more explicit in what you are asking.
 
Reply
  • Haha
  • Like
Likes chwala and Delta2

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
View full post »

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
View full post »

Similar threads

Quadratic Problem: Find Sum of Roots of 4 Equations
Replies
4
Views
1K
Using Power Reducing Formulas to rewrite Trig Expressions
Replies
7
Views
2K
What Steps Can Resolve a Trigonometric Equation Involving Sine and Cosine?
Replies
10
Views
2K
Conditions for Cubic Equation to Represent Curve
Replies
2
Views
1K
Modular Arithmetic: Solving Equations with 22x^2 = 11 mod 13
Replies
4
Views
2K
Solving these Simultaneous Equations
Replies
3
Views
2K
Conceptual question on equations of the form ##x=ay^2+by+c##
Replies
5
Views
2K
Find a and b to make this equation symmetric about the y-axis: y = ax^2 + bx^3
Replies
24
Views
3K
Simple geometry problem -- Find the perimeter of the triangle ABC
Replies
7
Views
3K
Linearizing an equation for Mixed-integer linear programming (MILP)
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top