Solving the following system of equations

  • Thread starter Spensy
  • Start date
2x+3y = 7, -> equation1
2x^2-3y^2 = -25; -> equation2

first of all tell me the type of equations

first i solve for y equation 1

y = (-2x +7)/3

now what should i do ?
 

phyzguy

Science Advisor
4,156
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Now plug that expression for y into equation 2 and solve for x. It will be a quadratic equation for x, so you will need the quadratic formula.
 
please i need more help can any 1 solve this equations my text book has a solution set
{(-1,3),(-13,11)}

please help me I'd be thankful to you.
 
2x+3y = 7, -> equation1
2x^2-3y^2 = -25; -> equation2

first of all tell me the type of equations

first i solve for y equation 1

y = (-2x +7)/3

now what should i do ?
So if y = (7-2x)/3, what is 3y2?
 

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