Solving the following system of equations

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Discussion Overview

The discussion revolves around solving a system of equations consisting of a linear equation and a quadratic equation. Participants are exploring methods to find the values of x and y that satisfy both equations.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents the equations 2x + 3y = 7 and 2x^2 - 3y^2 = -25, asking for the type of equations and how to proceed after solving for y.
  • Another participant suggests substituting the expression for y into the second equation to solve for x, indicating that it will result in a quadratic equation.
  • A different participant expresses a need for further assistance, mentioning a solution set from their textbook that includes the pairs {(-1,3), (-13,11)}.
  • A later post reiterates the initial equations and asks for clarification on the expression for y, specifically inquiring about the value of 3y^2.

Areas of Agreement / Disagreement

There is no consensus on the solution process, as participants are at different stages of solving the equations and some are seeking further clarification.

Contextual Notes

Participants have not fully resolved the steps needed to solve the system, and there are references to a textbook solution that may not be universally accepted or verified within the discussion.

Who May Find This Useful

Students or individuals seeking assistance with solving systems of equations, particularly those involving both linear and quadratic forms.

Spensy
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2x+3y = 7, -> equation1
2x^2-3y^2 = -25; -> equation2

first of all tell me the type of equations

first i solve for y equation 1

y = (-2x +7)/3

now what should i do ?
 
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Now plug that expression for y into equation 2 and solve for x. It will be a quadratic equation for x, so you will need the quadratic formula.
 
please i need more help can any 1 solve this equations my textbook has a solution set
{(-1,3),(-13,11)}

please help me I'd be thankful to you.
 
Spensy said:
2x+3y = 7, -> equation1
2x^2-3y^2 = -25; -> equation2

first of all tell me the type of equations

first i solve for y equation 1

y = (-2x +7)/3

now what should i do ?

So if y = (7-2x)/3, what is 3y2?
 

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