Solving the Laplace Equation for a Capacitor Setup

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SUMMARY

The discussion focuses on solving the Laplace Equation for a capacitor setup consisting of two parallel circular disc electrodes with radius R, separated by a distance of 2H and charged to potentials +U and -U. The Laplace Equation in cylindrical coordinates is presented as \[{\nabla ^2}\phi = \frac{1}{r}\frac{{\partial \phi }}{{\partial r}} + \frac{{{\partial ^2}\phi }}{{\partial {r^2}}} + \frac{{\partial ^2\phi }}{{\partial {z^2}}} = 0\]. The user seeks confirmation on the correctness of the boundary conditions defined for the potential distribution, which include specific values at z = H and z = -H, as well as conditions at various radial distances.

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  • Understanding of the Laplace Equation in cylindrical coordinates
  • Knowledge of electrostatics and capacitor theory
  • Familiarity with boundary value problems in partial differential equations
  • Basic concepts of potential distribution in electrostatic fields
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  • Review the derivation of the Laplace Equation in cylindrical coordinates
  • Study boundary value problems and their applications in electrostatics
  • Learn about numerical methods for solving partial differential equations
  • Explore the impact of boundary conditions on potential distributions in capacitors
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Students and professionals in electrical engineering, physicists working on electrostatics, and anyone involved in solving boundary value problems related to capacitors and potential fields.

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Homework Statement




The capacitor is assumed to consist of two parallel circular disc electrodes of radius R. The electrodes are of infinite small thickness, placed a distance 2H apart, and are equally and oppositely charged to potentials +U and -U. A metal cylinder is placed near the two electrodes and the position relationship can be found in the following picture:

http://i1021.photobucket.com/albums/af335/hectoryx/professional/1.jpg


Homework Equations



To solve the potential distribution in this situation, the Laplace Equation in cylindrical coordinate system is:

[tex]\[{\nabla ^2}\phi = \frac{1}{r}\frac{{\partial \phi }}{{\partial r}} + \frac{{{\partial ^2}\phi }}{{\partial {r^2}}} + \frac{{{\partial ^2}\phi }}{{\partial {z^2}}} = 0\][/tex]

The Attempt at a Solution



I am not sure about its boundary condition:

[tex]\[\left\{ {\begin{array}{*{20}{c}}<br /> {\phi = + {\rm{U}},\begin{array}{*{20}{c}}<br /> {} & {{\rm{z}} = {\rm{H}}} \\<br /> \end{array},0 \le r \le {\rm{R }}} \\<br /> {\phi = - {\rm{U}},\begin{array}{*{20}{c}}<br /> {} & {{\rm{z}} = - {\rm{H}}} \\<br /> \end{array},0 \le r \le {\rm{R}}} \\<br /> \end{array}} \right.\][/tex]

and

[tex]\[\begin{array}{l}<br /> \phi = {\phi _c},\begin{array}{*{20}{c}}<br /> {} & {{\rm{H}} + {\rm{d}} \le {\rm{z}} \le {\rm{H}}} \\<br /> \end{array} + {\rm{d}} + {\rm{L}},0 \le r \le {\rm{R}} \\ <br /> \frac{{\partial \phi }}{{\partial z}} = {\sigma _1},\frac{{\partial \phi }}{{\partial r}} = 0,\begin{array}{*{20}{c}}<br /> {} & {{\rm{z}} = {\rm{H}} + {\rm{d}}} \\<br /> \end{array},0 \le r \le {\rm{R}} \\ <br /> \frac{{\partial \phi }}{{\partial z}} = {\sigma _2},\frac{{\partial \phi }}{{\partial r}} = 0,\begin{array}{*{20}{c}}<br /> {} & {{\rm{z}} = {\rm{H}} + {\rm{d}}} \\<br /> \end{array} + {\rm{L}},0 \le r \le {\rm{R}} \\ <br /> \frac{{\partial \phi }}{{\partial z}} = 0,\frac{{\partial \phi }}{{\partial r}} = {\sigma _3},\begin{array}{*{20}{c}}<br /> {} & {{\rm{H}} + {\rm{d}} \le {\rm{z}} \le {\rm{H}}} \\<br /> \end{array} + {\rm{d}} + {\rm{L}},r = {\rm{R}} \\ <br /> \end{array}\][/tex]


Could anyone give me some help and tell me that whether the boundary conditions above are right?

Thanks very much!

Best Regards.

Hector
 
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chould anyone help me please? Really thanks!
 

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