Solving the Logarithmic Integral of Ln(y-1)/y^2 by Hand

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The discussion focuses on solving the integral of Ln(y-1) / y^2 by hand, a problem encountered in solid state physics homework. The solution involves using integration by parts, specifically letting u = ln(y-1) and dv = -1/y. Participants emphasize the importance of recognizing the need for partial fractions to simplify the second integral, which is crucial for completing the solution manually.

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I have been working on a solid state physics homework problem, and I have gotten the answer down to an integral that I am unsure how to do by hand. I can plug it into Mathematica, and I receive the correct answer (I am asked to show something) but I would like to know how to do this integral by hand.

Integral of Ln(y-1) / y^2
 
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It's an easy integration by parts. Let u=ln(y-1) and v=(-1/y). Your integral is u*dv. Is that enough of a hint? If not then for the second integral v*du use partial fractions.
 
Ahh... I tried the integration by parts approach, but wasn't sure where to go from there. I hadn't done partial fractions in a long while and did not notice I could separate it that easily. Thank you.
 

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