Solving the Mystery of Two Beads and a Frictionless Hoop

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SUMMARY

The discussion focuses on a physics problem involving two beads of mass m sliding down a frictionless hoop of mass M and radius R. The objective is to determine the maximum ratio of m to M such that the hoop remains grounded. Key equations referenced include the conservation of energy and forces acting on the hoop and beads, specifically 2mg cos²(θ) = Mg. The solution requires analyzing the forces and accelerations involved as the beads descend the hoop.

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Homework Statement



Two beads of mass m are initially at rest at the top of a frictionless hoop of mass M and radius R, which stands vertically on the ground. The beads are given tiny kicks, and they slide down the hoop, one to the rigth and one to the left. What is the largest value of m/M for which the hoop will never rise up off the ground?

Homework Equations



classical mechanics

The Attempt at a Solution



2mg cos^2(theta from top) = Mg ?

please help me get started, as this is an assignment question
 
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hi zheng89120! :smile:

(have a theta: θ and try using the X2 tag just above the Reply box :wink:)
zheng89120 said:
2mg cos^2(theta from top) = Mg ?

where did that come from? :confused:

start with conservation of energy to find the speed as a function of θ

then find the acceleration

then find the force from the hoop on each mass

then find the force on the hoop from each mass …

when will that be enough to lift the hoop? :smile:
 

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