Solving the Schrodinger Equation for V(x)=A sech^2(αx)

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Mahasweta
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1. How can I solve the Schrödinger equation for a potential V(x)= A sech^2(αx) ? How do I come to know that whether sech(αx) is a non-node bound state of the particular or not?




2. p^2/2m + V(x) = E



3. exp(kx)[A tanh(αx) + C]
 
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Welcome to PF;
How can I solve the Schrödinger equation for a potential V(x)= A sech^2(αx) ?
You put the potential into the Schrödinger equation with appropriate boundary conditions - just like any DE.
Note: $$\text{sech}(x)=\frac{2e^{-x}}{1+e^{-2x}}$$

How do I come to know that whether sech(αx) is a non-node bound state of the particular or not?
... "non bound state of a particular" what? That sentence is incomplete.

i.e. are you saying that you are given ##\psi=\text{sech}(ax)## and you want to know if it is the wavefuction of a bound energy eigenstate of the potential you've been given, if it is a bound state of any potential or what?

You can figure out a lot about a potential by plotting it and using your experience of solving for different wells - like what sorts of potentials have bound states etc.
 
I meant that for a particular potential how do I come to know that among a set of wave functions for that potential which one is non-node bound state?