Solving the time dependant schrodinger eqn in dirac (bra ket) notation

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The discussion focuses on solving the time-dependent Schrödinger equation in Dirac (bra-ket) notation, specifically for the state |PSI(0)> expressed as a linear combination of basis states |PSI1> and |PSI2>. The user initially decomposes |PSI1> and |PSI2> into |UP> and |DOWN> states but struggles with the application of the time evolution operator. The solution involves using the exponential term EXP(-iEt/h-bar) to describe the time evolution of the state, leading to the final expression for |PSI(t)> as a function of time.

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rwooduk
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given:

at t=0 |PSI(0)> = 1/2 |PSI1> + (SQRT3)/2 |PSI2>


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my attempt so far:

we can write

|PSI1> = 1/2 |UP> + 1/2 |DOWN>

|PSI2> = (SQRT3)/2 |UP> + (SQRT3)/2 |DOWN>

therefore

|PSI(0)> = 1/2 |UP> + 1/2 |DOWN> + (SQRT3)/2 |UP> + (SQRT3)/2 |DOWN>



but then what do i do? the lecturer hasnt shown us how to solve the time DEPENDENT Schrödinger eqn in ket notation, infact i don't recall her showing us how to solve the time independent eqn either, only something like this:

|PSI(x)> = I(x)|PSI> = INTEGRAL BETWEEN -INF AND +INF of dx|x><x|PSI>

so do i use the Identity to give some sort of integral for |PSI(O)>??

I'm at a total loss and spent another 2+ hours going around in circles.

If someone could point me in the right direction, or even suggest a web page that details how to solve the time independent Schrödinger eqn in dirac notation, it would REALLY be appreciated.

edit

I found the solution on the web, well kind of, my question needs in terms of base vectors, but;

at t=o |PSI> = SUM Cn|PSIn>

at t>0 |PSI> = SUM Cn|PSIn> EXP (-iEt)/h-bar

where does the EXP term come from?? I know where it comes from in normal notation but how to get an exp term from |UP>'s and |DOWN>'s ?? and they are only vectors anyway, how can an EXP term be directional?? totally confused.
 
Last edited:
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it's ok found something in the book

t=0 |PSI(0)> = SUM αi|PSIi>

t>0 |PSI(t)> = SUM αi EXP (-iEit/h-bar) |PSIi>

from

ih-bar d/dt |PSI> = H |PSI>therefore my answer (i think) will simply be

|PSI(t)> = (1/2 |PSI1> + (SQRT3)/2 |PSI2>)EXP (-iEit/h-bar)

= (1/2 (|UP> + |DOWN>) + (SQRT3)/2 (|UP> + |DOWN>) ) EXP (-iEit/h-bar)or maybe I am way off? will update when the answers come into help others
 
Last edited:
The homework template is there for a reason. Could you please provide the complete problem statement?
 

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