- #1

Mspike6

- 63

- 0

First:

y= Cos

^{3}(5x

^{2}-6)

Solution :

Y' = 3cos

^{2}(5x

^{2}-6)(-sin(5x

^{2}-6))(10x)

y'= 30xCos

^{2}(5x

^{2}-6)(-sin(5x

^{2}-6))

Is the correct ?

Second

Y=3sin

^{4}(2-x)

^{-1}

I don't understand what do i have to do with the -1 (the power to the bracket )

so i add it to the 4 (the power of sin ) ?

am not sure

Any help is appreciated