Solving Tricky Pauli Matrices with Einstein Notation

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The discussion revolves around recovering a calculation involving 4x4 matrices in SL(2,C) and the application of Pauli matrices using Einstein notation. The user is struggling to express the expansion of K'=AKA^{\dagger} in this notation and seeks clarification on the properties of Pauli matrices. There is confusion regarding the correct placement of indices and the interpretation of infinitesimal changes in the transformation. The conversation highlights the need for more context and explicit development of the expression in index notation to derive the desired result. Ultimately, the user is encouraged to clarify their approach to the product rule in the context of their calculations.
emma83
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Hello,
I am trying to recover the following calculation (where K,A are 4x4 matrices in SL(2,C)):

--(start)--
"We expand K'=AKA^{\dagger} in terms of k^a and k'^{a}=(\delta_a^{b} + \lambda_a^{b} d\tau)k^b. Multiplying by a general Pauli matrix and using the relation \frac{1}{2}tr(\sigma_{a}\sigma_{b})=\delta_{ab} yields the expression:
<br /> \lambda_b^{a} = \frac{1}{2}\eta^{ac}tr(\sigma_{b}\sigma_{c}A+\sigma_{c}\sigma_{b}A^{\dagger})<br />."
--(end)--

I have been playing with the relations for a while but I guess I miss some knowledge on the properties of Pauli matrices because I don't manage to find the result. In particular, what would the "expansion" of AKA^{\dagger} (which I guess is necessary here?) look like in Einstein summation notation ? Any help would be extremely appreciated!
 
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the answer lies on wikipedia.
 
ryuunoseika said:
the answer lies on wikipedia.

Well, give a link, then :rolleyes:which article? :smile:
 
Well I had of course already checked beforehand the wikipedia page on Pauli matrices (http://en.wikipedia.org/wiki/Pauli_matrices) but had not found a relation to solve this problem... So Ryuunoseika, which article are you talking about ?
 
Something here seems either not quite right or incomplete.

If k&#039;^{a} = \left(\delta_b^{a} + \lambda_b^{a} d\tau \right) k^b (careful with index placement) and d \tau is infinitesimal (?), then k&#039; and k differ by an infinitesimal amount, so the transformation is an infinitesimal version of K&#039;=AKA^{\dagger}. Then, the sum in final result could come from the product rule.

I'm just guessing. More context is needed.
 
Dear George,

Thanks a lot for your answer. First, yes sorry I misplaced the indices in the first relation, the correct relation is:
k&#039;_{a}=(\delta_a^{b} + \lambda_a^{b} d\tau)k_b

Concerning d\tau, it is actually a \delta u, where u is the affine parameter along the trajectory of a photon.

But what do you mean by "product rule" ? Do I have to develop explicitely AKA^{\dagger} in indices notation and try to recover at the end the A and A^{\dagger} which appear in the trace ?
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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