Solving Two Identical Conduction Spheres Problem

Click For Summary
To solve the problem involving two identical conduction spheres, the electrostatic force between them can be calculated using Coulomb's law. After connecting the spheres with a conducting wire, the charges will redistribute until they reach equilibrium, resulting in both spheres having the same net charge. The average of the two initial charges must be calculated, taking into account their signs, to determine the new charge on each sphere. The same Coulomb's law equation can be applied to find the electrostatic force after equilibrium is reached. Understanding the charge redistribution is crucial for solving part b) of the problem effectively.
AznBoi
Messages
470
Reaction score
0

Homework Statement


Two identical conduction spheres are placed with their centers 0.30m apart. One is given a charge of 12 x 10 ^-9 C, the other a charge of -18 x 10 ^-9 C a) Find the electrostatic force exerted on one sphere by the other. b) The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached.

Homework Equations


F=k(q1)(q2)/r^2 C

The Attempt at a Solution


I already solved a). It was really easy because all I did was plug in the correct information with the correct variables and solved for the electrostatic force between the objects.

How in the world do you start part b)?? Equilibrium means that the net force (F) will equal zero right? However, that isn't true because there is a force in the answer key. Mabye I'm thinking about the motion force and not the electrostatic force. Is there always a consistent electrostatic force?

Please. Can someone help me start part b) of the problem? I'm clueless here. Do you still use the same equation? I know that you can never just keep plugging in numbers to solve for these problems lol. I want to understand the concepts as well. Thanks! :smile:
 
Physics news on Phys.org
note when there is a conducting wire connecting the two sphere... charges will re-distribute themselves so that both spheres carry the same net charge...
 
Does that mean I have to find the average of the two charges and then plug them into the equation? If I find the average, do I use the absolute value of the charges or do I include any negative signs?
 
AznBoi said:
Does that mean I have to find the average of the two charges and then plug them into the equation? If I find the average, do I use the absolute value of the charges or do I include any negative signs?

Can someone please tell me if the above procedure will work? I know for a fact that the electrons (charges) are distributed evenly. How should one do this? My method is quoted above. Will it work? Thanks.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
21
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
610
Replies
6
Views
2K
Replies
1
Views
2K