Solving Umax with Pmax and Ohms

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Ren_Majer
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Brief personal intro, I have last time studied physics about 12 years ago.

I am now starting in 2 weeks time in a university and there is mandatory physics course so I am trying to relearn and learn as much as I can before that time.

For that reason I am trying to solve textbook tasks from my old physics books.

I have never been good at maths nor physics atleast not calculations. Thus I appreciate thorough-Step by Step explanations so I can understand the solution.

Thank you for your time


Homework Statement



How large voltage U , can be attached to the circuit , when both the resistance have an Pmax of 0,25 W ?

R1 = 120Ω
R2=180Ω

They are in series.

Answer is :
Umax = 11

Homework Equations



P = U * I
U = R * I


The Attempt at a Solution




0,25*120= 0,002083333333
0,25*180= 0,003888888889

0,002083333333 + 0,003888888889=0,00347222222

0,00347222222*120 = 0,416666664
0,00347222222*180 = 0,624999996

4,16666664+6,24999996= 10,41666666
 
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Since they're in series, they have the same current through them. If you start with a low current and slowly ramp it up, do you know which of the resistors will reach its thermal limit first?
 
milesyoung said:
Since they're in series, they have the same current through them. If you start with a low current and slowly ramp it up, do you know which of the resistors will reach its thermal limit first?

No , it is not mentioned on the task nor which direction the current will go
 
Ren_Majer said:
No , it is not mentioned on the task nor which direction the current will go
Just assume that you can control the current through the resistors, I promise you that I'll get to the point shortly :smile:

Say you have a current of 1 A through the resistors. How much power is then dissipated in each resistor?