Solving Unintuitive Homework: An Example of C ≠ f^(-1)(f(c))

  • Thread starter Thread starter Kosh11
  • Start date Start date
  • Tags Tags
    Example Homework
Click For Summary
The discussion revolves around the proof of the statement C ≠ f^(-1)(f(c)), where participants explore the implications of this inequality. One user suggests starting with small discrete sets to find a suitable example, specifically mentioning A = {a, b} where both map to the same point. The conversation also touches on whether differentiable maps affect the equality, with some uncertainty expressed about the relevance of differentiability in this context. Ultimately, the example provided is deemed sufficient for illustrating the concept. The thread highlights the complexities of understanding function mappings and their inverses.
Kosh11
Messages
5
Reaction score
0

Homework Statement



741xH.png


Homework Equations





The Attempt at a Solution



I don't know how to start a proof for this. Intuitively I would think think that C = f^(-1)(f(c)), which would imply that C is a subset of f^(-1)(f(c)), however that is not the case and the problem asks for an example when that is not true. Does this mean that f(C) sends all elements c of C from A to B and that f^(-1) sends all elements c of C from B to A?
 
Physics news on Phys.org
its good to start with small discrete sets and see if you can find a good example

how about considering A = {a,b} both mapped to the same point f(a) = f(b) = d
 
Thanks I kind of figured it out. One questions would a differentiable map be considered an example where if you have f(a) = d then then f^(-1)(f(a)) wouldn't necessarily equal a?
 
I'm not sure why you would need to consider differntiability? You;re just looking at maps between sets

the example I gave in post #2 should be sufficient...
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
2K
Replies
15
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K