Solving Vector 1: Is arctan the Only Way?

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SUMMARY

The discussion focuses on determining the angle of vector V1 = -6i + 8j using the arctan function. The initial calculation yields an angle of -53 degrees, which is in the fourth quadrant, leading to confusion about its actual position in the second quadrant. To find the correct angle, users can apply the formula 180 - 53 to obtain 127 degrees. The ATAN2 function, available in various programming languages, is recommended for directly calculating the angle in the correct quadrant without additional adjustments.

PREREQUISITES
  • Understanding of vector components and their representation in Cartesian coordinates.
  • Familiarity with trigonometric functions, specifically arctan and its limitations.
  • Knowledge of the ATAN2 function and its application in programming languages.
  • Basic skills in angle measurement and quadrant identification in the Cartesian plane.
NEXT STEPS
  • Research the ATAN2 function in programming languages such as Python or Java.
  • Study the properties of angles in different quadrants and their implications in vector mathematics.
  • Explore graphical methods for vector representation and angle determination.
  • Learn about the limitations of the arctan function and alternative methods for angle calculation.
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Students studying vector mathematics, educators teaching trigonometry, and programmers implementing vector calculations in software development.

brycenrg
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Homework Statement


V1 = -6i + 8j

Homework Equations


arctan theta

The Attempt at a Solution


arctan 8/(-6) = -53 deg

To me this is a little confusing because its negative 53 degrees which is in the fourth quadrant but i reality its in the second quadrant.
Do I always have to do an additional math plus graphical test to see where it is and the actual degree of vector 1?
For example To see the degree of V1 i have to do 180 - 53 to get an angle of 127 degrees.
But is there a way that I just plug it in and it gives me the correct degree in the right quadrant right away?
 
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brycenrg said:

Homework Statement


V1 = -6i + 8j

Homework Equations


arctan theta

The Attempt at a Solution


arctan 8/(-6) = -53 deg

To me this is a little confusing because its negative 53 degrees which is in the fourth quadrant but i reality its in the second quadrant.
Do I always have to do an additional math plus graphical test to see where it is and the actual degree of vector 1?
For example To see the degree of V1 i have to do 180 - 53 to get an angle of 127 degrees.
But is there a way that I just plug it in and it gives me the correct degree in the right quadrant right away?
Plug it in what? Your calculator?

Most calculators only determine the principal angle for the inverse tangent function, which is the angle such that -π/2 ≤ θ ≤ π/2.

Some computer languages have a built in function called ATAN2, which takes 2 arguments. This function can calculate the proper quadrant in which the angle falls.

Still, since you are furnished the components of this vector, you should be able to tell by inspection in which quadrant the angle falls. It's not that difficult.
 

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