Solving Vector C: 3.00A - 4.00B

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Homework Help Overview

The discussion revolves around expressing the vector C in terms of unit vectors, specifically given the equation C = 3.00A - 4.00B, where vectors A and B are defined with their respective components.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the correct method for combining vectors A and B, questioning the steps involved in scalar multiplication and vector subtraction. There is confusion regarding the order of operations and the correct application of coefficients to vector components.

Discussion Status

Some participants have provided clarifications on the proper approach to the problem, emphasizing the need to multiply each vector by its respective scalar before performing the subtraction. There is ongoing exploration of the calculations involved, with some participants expressing uncertainty about the next steps.

Contextual Notes

Participants are adhering to forum guidelines that discourage revealing complete solutions, focusing instead on guiding understanding and clarifying the problem setup.

Heat
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Homework Statement



Use unit vectors to express the vector C, where C = 3.00A - 4.00B

Keep in mind that C, A, and B are vectors, I could not get the Latex to work.

Homework Equations



There are no relevant equations, but I don't know if the question above the one I am asking refers to this, as I got that:

Vector A = 1.23 i + 3.38j
Vector B = -2.08i - 1.2j

The Attempt at a Solution



My attempt would be to subtract -2.08 from 1.23 leading the final i to be 3.31 (as it's subtracting and negative with negative = +.) and the final j to be 4.58.

If this is how it is suppose to go, then do I plug those numbers in for A and B, multiply time their coeffiecients

ex: 3.00 (3.31) - 4.00 (4.58) = C ?

:confused:
 
Last edited by a moderator:
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Heat said:
My attempt would be to subtract -2.08 from 1.23 leading the final i to be 3.31 (as it's subtracting and negative with negative = +.) and the final j to be 4.58.

If this is how it is suppose to go, then do I plug those numbers in for A and B, multiply time their coeffiecients

ex: 3.00 (3.31) - 4.00 (4.58) = C ?

:confused:

No. What you're attempting to do is to multiply the differences of the i and j components by 3 and 4, respectively. What you actually need to do is multiply the vector A by 3, multiply the vector B by 4 and then take their difference. Multiplying a vector by a scalar is equivalent to multiplying each component of the vector by that scalar.
 
*EDIT* deleted solution
You were solving for [tex]3.00(\vec{C}\hat{i}) + 4.00(\vec{C}\hat{j})[/tex]

But it asks for [tex]3.00\vec{A} - 4.00\vec{B}[/tex] or
[tex]3.00\vec{A}\hat{i} + 3.00\vec{A}\hat{j} - (4.00\vec{B}\hat{i} + 4.00\vec{B}\hat{j})[/tex]
 
Last edited:
odie5533, as per the forum's guidelines, you are not supposed to reveal the solution to the problems posted in the homework help forums. At most, you can guide the person to the solution. Apart from being a rule, it is also good practice to not provide the solution, since by copying the answer the poster does not gain anything apart from a few points for a single question.
 
Last edited:
Sorry neutrino. Fixed my response.
 
@ odie5533 Don't worry about me looking at the solution, I logged in too late:rolleyes: , but I thank you for the explanation.

[tex]3.00\vec{A}\hat{i} + 3.00\vec{A}\hat{j} - (4.00\vec{B}\hat{i} + 4.00\vec{B}\hat{j})[/tex]


Here is what I did, I just don't know where it goes from here.

[3.00 (1.23 i) + 3.00 ( 3.38j)] - [(4(-2.08i) + 4(-1.2j))] =

3.69i + 10.14j + 8.32i + 4.8j

Do I add the like terms resulting into:

12.01i + 14.94j

:rolleyes:

PS: I'm here to learn, as I would need to know all of this later on.:approve:
 
Yes, Heat. Exactly how you have done it is right. First multiplying the components by the constant, then performing the vector subtraction.
 

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