Solving Vectors and Forces Homework Problem

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The discussion focuses on solving a physics problem involving a sign weighing 150N suspended by two wires at angles of 50 degrees and 40 degrees to the walls. The initial calculations for the tension in the first wire were incorrectly stated as 233.36N and for the second wire as 195.81N. The correct approach involves using both vertical and horizontal components of the forces, leading to the equations F1cos50º + F2cos40º = 150 for vertical equilibrium and additional equations for horizontal equilibrium to solve for the tensions accurately.

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Homework Statement



A sign weighs 150n and is suspended on 2 wires between 2 walls, 1 at 50 degrees to the wall and the other at 40 deg to the other wall. What is the tension in each wire?

Homework Equations





The Attempt at a Solution



For the 1st wire F=150/cos50
=233.36N
2nd wire F=150/cos40
=195.81N
Is this likely to be correct I can't find any simular examples to help me out.
 
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Welcome to PF!

Hi P.townsville! Welcome to PF! :smile:

(have a degree: º :wink:)
P.townsville said:
A sign weighs 150n and is suspended on 2 wires between 2 walls, 1 at 50 degrees to the wall and the other at 40 deg to the other wall. What is the tension in each wire?

For the 1st wire F=150/cos50
=233.36N
2nd wire F=150/cos40
=195.81N

Nooo :redface:

you're saying F1cos50º = 150, F2cos40º = 150.

But if you're taking vertical components, that'll be F1cos50º + F2cos40º = 150, won't it?

Hint: you need one equation for both vertical components, and another equation for both horizontal components, and then a bit of algebra and trig. :smile:

(Alternatively, find a direction in which you can ignore one of the tension forces :wink:)
 

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