Solving Voltage Capacitors: Step-by-Step Guide

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    Capacitors Voltage
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Homework Help Overview

The discussion revolves around a problem involving capacitors and voltage, specifically focusing on the calculations related to charge (q), capacitance (C), and voltage (V). Participants are attempting to understand the relationships between these variables in the context of a circuit setup.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss their calculations involving the equation q=V.C and the total capacitance in the circuit. Questions arise about the validity of their results, particularly regarding the value of Cx and its relationship to other capacitances in the circuit.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning the correctness of their answers. Some participants express uncertainty about the values derived, particularly regarding the capacitance Cx, and seek clarification on whether to eliminate the unknown capacitance in their calculations.

Contextual Notes

There is mention of a textbook answer that conflicts with participants' calculations, leading to confusion about the correct value of Cx. The original poster and others are navigating through differing interpretations of the problem setup and the implications of their calculations.

FiskiranZeka
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Capacitors - Voltage [ Solved ]

Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
 

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FiskiranZeka said:
Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
Welcome to PF,

That's not the way it works here. We will help you through your homework, but we won't do it for you.

What have you tried thus far?
 
You are asking how i treid to solve this right ?
So, i explain;

q=V.C

3C + C --> 4C
q = 4C. V1

On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Cx = 1/2 is the wrong answer, what i have found...
 
FiskiranZeka said:
You are asking how i treid to solve this right ?
So, i explain;

q=V.C

3C + C --> 4C
q = 4C. V1

On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Everything looks good up until this point. Your next statement is incorrect:
Cx = 1/2
Picking up from your previous like you have:

[tex]8C_x = 4C[/tex]

Hence,

[tex]C_x = \frac{1}{2}{\color{red}\bold{C}}[/tex]

You still need to eliminate the unknown Capacitance (C). Do you follow?
 
Yeah sorry,
my calculations say -->
Cx = 1/2 C

But correct answer is Cx = 8C

As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
 
FiskiranZeka said:
Yeah sorry,
my calculations say -->
Cx = 1/2 C

But correct answer is Cx = 8C

As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.

Wherever you got the 'correct' answer of Cx = 8*C is incorrect.
 
Hootenanny said:
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.

Wherever you got the 'correct' answer of Cx = 8*C is incorrect.

Yeayy ! Thank you !
I have also doubt that 8C Could be wrong, but i couldn't be sure, 'cos it's Physic Book's answer. Anyway, now I am glad :))

// Problem Solved.
 

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