Solving Wave Packet Propagation: Analyzing Group and Phase Velocities

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SUMMARY

The discussion focuses on the analysis of wave packet propagation, specifically examining the phase and group velocities derived from the wave packet equation \(\Psi (x,t) = \int_{k-\Delta k}^{k+\Delta k} A \cos\left[k'(x-ct)\right] dk'\). The integral is solved to yield \(\Psi (x,t) = \frac{2A \Delta k}{\Delta k (x-ct)} \cos[k(x-ct)] \sin[\Delta k (x-ct)]\). It is established that the wave packet moves in the positive direction, and the width of the packet, given by \(\frac{2 \pi}{\Delta k}\), remains constant over time due to the linear dispersion relation.

PREREQUISITES
  • Understanding of wave packet theory
  • Familiarity with dispersion relations in physics
  • Knowledge of trigonometric functions and integrals
  • Basic concepts of phase and group velocities
NEXT STEPS
  • Study the derivation of phase velocity in wave mechanics
  • Explore group velocity and its implications in wave propagation
  • Investigate the effects of non-linear dispersion relations on wave packets
  • Learn about the mathematical techniques for solving integrals in wave physics
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Physicists, students of wave mechanics, and researchers interested in wave propagation and its mathematical foundations will benefit from this discussion.

stunner5000pt
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Consider a wave packet represented by

[tex]\Psi (x,t) = \int_{k-\Delta k}^{k+\Delta k} A \cos\left[k'(x-ct)\right] dk'[/tex]

A constant and ck' is the dispersion relation

SOlve th integral and describe the propagation properties of this wave packet. Assume this means that the phase and group velocities as well as width of the packet. Also explicitly show if/how the width changes in time.its easy to do this integral...

[tex]\Psi (x,t) = \frac{2A \Delta k}{\Delta k (x-ct)} cos[k(x-ct)] \sin[\Delta k (x-ct)][/tex]

propagation properties...
WEll it seems that the wave is moving right (positive direction) by virtue of the argument of the cosine.

Width of the packet is [itex]\frac{2 \pi}{\Delta k}[/itex]Does Delta k change in time??

i cnat think of anything to solve here... do they mean DERIVE the formulas for group and pahse velocities??
 
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You're right, the wave is moving right since the x,t dependence is x-ct (as opposed to x+ct), and the width doesn't change in time, since this is a wave (time only acts to translate the shape in space). The phase and group velocities are the same here since the dispersion relation is linear.
 

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