Solving Whole Integer Solutions for Easy Math Quesiton 3 (x^2)=a^2

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SUMMARY

The equation 3(x^2) = a^2 has only one solution in whole integers, which is x = 0 and a = 0. The discussion highlights that for integers a and x, the equation leads to a contradiction involving the irrational number √3, making it impossible for any non-zero integer solutions to exist. The topic was initially misclassified under "Tensor Analysis and Differential Geometry" but is more accurately categorized within number theory.

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3(x^2)=a^2

When are a and x whole integers?
 
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In what sense does this have anything to do with "Tensor Analysis and Differential geometry"? I'm moving it to "number theory".

In any case, if 3x2= a2 for a and x integers, then we must have
[itex]a= x\sqrt{3}[/itex] which is impossible unless x= a= 0. It implies [itex]\sqrt{3}= a/x[/itex] but [itex]\sqrt{3}[/itex] is irrational.

The only integer solution to 3x2= a2 is x= a= 0.
 

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