Modulus Inequality Help: Solving |x/2 + 3| > 3-x^2 and |e^x/2 - 3| > 3-e^(2x)

[truewt]

Homework Statement

Solve $$| \frac{x}{2} +3 | > 3-x^2$$
Hence, solve $$| \frac{e^x}{2} -3 | > 3-e^{2x}$$

Homework Equations

The Attempt at a Solution

I've solved the first part. But I have no clue what is the link to the second part?! could there be just typo to the question?? I can't find any links...

 

[rock.freak667]

Let u=e^x

and it becomes

$$|\frac{u}{2} +3 | > 3-u^2$$

 

[truewt]

Didn't help.

Anyway I figured the solution already.

should be let $$u= - e^x$$