Solving Work Done Problem: Minimize Work, Angle & Magnitude of Force

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Homework Help Overview

The problem involves determining the optimal angle at which to apply a force to minimize the work done in moving a block across a horizontal surface, considering factors such as weight, friction, and distance. The context is rooted in mechanics, specifically focusing on work and force interactions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the possibility of applying a force at 90 degrees to minimize work, questioning whether this would allow for the movement of the block. There is also speculation about the implications of applying a force at angles very close to 90 degrees.

Discussion Status

Participants are actively engaging with the problem, exploring different angles and their implications on work done. Some guidance is emerging regarding the necessity of a horizontal component to facilitate movement, although no consensus has been reached.

Contextual Notes

There is mention of the problem being part of a college assessment, which may impose specific constraints or expectations on the solution approach.

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Homework Statement


There is a block of weight mg sitting on a horizontal table with a coefficient of kinetic friction u, at what angle to the horizontal should one direct a driving force to minimise work done in moving the block a horizontal distance of 10m with nonzero velocity and what is the magnitude of that work?

Homework Equations


W=integral(F.ds)
F=uR

The Attempt at a Solution


Looking at this problem I cannot see why it would not be 90degrees and zero work being done because the direction of motion would be perpendicular to the force so F.ds is 0. But this is a 7 mark question surely that explanation isn't worth 7 marks have I missed something?
Thank you
 
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sorax123 said:
Looking at this problem I cannot see why it would not be 90degrees and zero work being done because the direction of motion would be perpendicular to the force so F.ds is 0.
That would certainly minimize the work! But would that allow you to move the block as required?
 
Doc Al said:
That would certainly minimize the work! But would that allow you to move the block as required?
So would you say 89.999999999...?
 
On second thought, I think you are right. (For all practical purposes: yes, you'd need some slight horizontal component.) I suspect the person creating the problem didn't realize this. (I suspect this is not a textbook problem.)
 
Doc Al said:
On second thought, I think you are right. (For all practical purposes: yes, you'd need some slight horizontal component.) I suspect the person creating the problem didn't realize this. (I suspect this is not a textbook problem.)
It is a college assessed problem bit annoying really
 

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