Solving Work Problem: Kinetic Energy of Toy Car After Braking

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Homework Help Overview

The discussion revolves around a physics problem involving the kinetic energy of a toy car after it brakes. The car initially has a kinetic energy of 6.4 J and experiences a frictional force while sliding a certain distance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between work, force, and distance to determine energy loss during braking. Some question how to calculate the remaining kinetic energy after this work is done.

Discussion Status

Several participants have provided calculations related to the work done by friction and its impact on the kinetic energy of the car. There is an ongoing exploration of the conservation of energy principle, with different interpretations of how to apply it to find the final kinetic energy.

Contextual Notes

Participants are working within the constraints of the problem, including the initial kinetic energy and the specific values for force and distance. There is some uncertainty about the correct application of formulas and the interpretation of energy loss.

Dwrigh08
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The toy car is sliding with a kinetic energy of 6.4 J when it locks up its tires (obviously, the toy driver slammed on the toy brakes) and slides for 62 cm, while a frictional force of 0.63 N acts against it. What is the kinetic energy (in Joules) of the car after this frictional work is done?

I am not sure where to even start.
 
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Work = force * distance. How much energy is lost in braking, how much does it have left.
 
Since W=Force * distance then W = .63N * .62m, So W = .3906Nm with = .39 J. Would you then subtract the Jules? which would = 6.01 Joules
 
From conservation of energy you know that ke(start) = ke(end) + energy lost.
You know the ke at the start, you have found the energy lost - so ke at the end is easy.
 

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