Solving Zinc Carbon Cell Equation: 2MnO2 + 3H2

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The discussion centers around the reactions occurring in a Leclanché cell, specifically regarding the role of manganese (IV) oxide as a depolarizer and the interaction with hydrogen. Participants express confusion over the equations related to the cathode reactions, noting that hydrogen gas appears to be absent from the overall reactions provided. The key equation mentioned, 2MnO2 + 3H2 --> 2MHO(OH) + 2H2O, is highlighted for its imbalance in oxygen. Various equations are presented, including those involving ammonium ions and manganese oxide, but they consistently lack hydrogen gas in the final products. The inquiry seeks clarity on the specific reaction between manganese oxide and hydrogen, emphasizing the need for accurate chemical representation in the context of the Leclanché cell.
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The hydrogen liberated at the cathode would coat the electrode so polarises the cell. And manganse (IV) oxide is used as a depolariser. I got an equation in my notes:

2MnO2 + 3H2 --> 2MHO(OH) + 2H2O.

But evidently the oxygen doesn't balance.

I tried looking on the internet but still no equation. Can someone help?
(also the overall equation does not contain hydrogen at all, can someone explain that?)

Thanks.
 
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I found this:

Cathode: 2 NH4+ (aq) + 2 MnO2 (s) + 2e- --> Mn2O3 (s) + 2 NH3 (aq) + H2O (l)

But hydrogen is not in the equation. I want to know exactly the reaction between manganese oxide and hydrogen gas.
 
From my notes i got:

2NH4+ + 2e- --> 2NH3 + H2



However another source gives different equations:
Cathode: 2 MnO2(s) + 2 NH4+(aq) + 2 e- ---> Mn2O3(s) + NH3(aq) + H2O

2 MnO2(s) + 2 NH4+(aq) + Zn(s)  Mn2O3(s) + NH3(aq) + H2O + Zn2+(aq)

so there nothing about hydrogen gas?
 
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