Solving Zinc Carbon Cell Equation: 2MnO2 + 3H2

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SUMMARY

The discussion centers on the chemical reactions involving manganese (IV) oxide (MnO2) and hydrogen gas (H2) in a zinc carbon cell. The participant seeks clarification on the overall reaction equations, noting discrepancies in the presence of hydrogen. The key equations referenced include 2MnO2 + 3H2 --> 2MHO(OH) + 2H2O and variations involving ammonium ions (NH4+), leading to products like Mn2O3 and NH3. The participant highlights the absence of hydrogen in the final equations, prompting a request for further explanation.

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garytse86
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The hydrogen liberated at the cathode would coat the electrode so polarises the cell. And manganse (IV) oxide is used as a depolariser. I got an equation in my notes:

2MnO2 + 3H2 --> 2MHO(OH) + 2H2O.

But evidently the oxygen doesn't balance.

I tried looking on the internet but still no equation. Can someone help?
(also the overall equation does not contain hydrogen at all, can someone explain that?)

Thanks.
 
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I found this:

Cathode: 2 NH4+ (aq) + 2 MnO2 (s) + 2e- --> Mn2O3 (s) + 2 NH3 (aq) + H2O (l)

But hydrogen is not in the equation. I want to know exactly the reaction between manganese oxide and hydrogen gas.
 
From my notes i got:

2NH4+ + 2e- --> 2NH3 + H2



However another source gives different equations:
Cathode: 2 MnO2(s) + 2 NH4+(aq) + 2 e- ---> Mn2O3(s) + NH3(aq) + H2O

2 MnO2(s) + 2 NH4+(aq) + Zn(s)  Mn2O3(s) + NH3(aq) + H2O + Zn2+(aq)

so there nothing about hydrogen gas?
 
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