Someone with a math computer program

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SUMMARY

The discussion revolves around solving two systems of equations involving variables a, b, x, and y, which represent equilibrium probabilities in a game theory context. The user seeks assistance with these equations due to a lack of access to Mathematica. A participant points out that the equations are overdetermined, indicating that there are more equations than unknowns, leading to either redundancy or no solution. Verification with Mathematica confirms that the solution set is empty.

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  • Understanding of systems of equations
  • Familiarity with game theory concepts
  • Knowledge of linear algebra principles
  • Experience with mathematical software like Mathematica
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  • Research methods for solving overdetermined systems of equations
  • Learn how to use Mathematica for solving algebraic equations
  • Explore game theory equilibrium concepts in more depth
  • Study linear algebra techniques for analyzing redundant equations
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Mathematicians, game theorists, students studying linear algebra, and anyone interested in solving complex systems of equations.

msmith12
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so, this is probably not exactly posted in the right place, but I was wondering if someone could enter a couple of things into a math program for me. I have two simple systems of equations and need the values for them, and unfortunately, don't have mathematica on this computer, and I reallly don't want to try these out with pencil and paper... so without further adiou...

<br /> (1-a-b)(1+4x+3y)=a(4-4x-y)=b(2+y)<br />
<br /> (1-x-y)(1+6a-b)=x(4-2a+8b)=y(6-5a-6b)<br />

and...

<br /> a(1+4x+3y)=b(4-4x-y)<br />
<br /> x(4a+2b)=y(6a+b)=(1-x-y)(a+7b)<br />

i need to find the values of a,b,x,y for each set of equations.

(in case you were wondering where these came from, they are the equilibrium probabilites that player A chooses 1,2,3 and player B chooses a,b,c)

thanks a bunch

~tired of number crunching
 
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It appears that your equations are overdetermined. You only have 4 unknowns, but you have 7 equations, which either means that 3 of them are redundant, or there is no solution. I don't have a math program either, so I can't verify that statement.

BTW, this really belongs more in the Linear Algebra forum.
 
I checked with Mathematica and the solution set is empty.
 

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