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Something about exterior algebra

  1. Jul 10, 2009 #1
    1.how to prove div(A × B) = (rot A)· B - A ·(rot B)
    2.d(ω1(A) × ω1(B))=?
     
  2. jcsd
  3. Jul 10, 2009 #2

    HallsofIvy

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    The simplest way to do 1 is just to go ahead and write out the component by component formula for both sides (I assume that "rot A" is what I would call "curl A": [itex]\nabla \times A[/itex].

    For 2, use the product rule.
     
  4. Jul 10, 2009 #3
    For 2, use the product rule.[/QUOTE]

    What's the rule?
     
  5. Jul 10, 2009 #4

    HallsofIvy

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    If you are working with exterior algebras and "differentials", surely you have taken Calculus I- and all I am talking about is the extension of the "product rule" from Calculus I extended to vectors. You should have seen that in multi-variable Calculus.
     
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