Sound and kinematic problem solving

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Homework Help Overview

The problem involves calculating the total time it takes for a man to hear the sound of a stone hitting the bottom of a 120m deep can, considering the temperature of the air at 20 degrees Celsius. The subject area includes kinematics and sound propagation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the time for the stone to fall using a kinematic equation, expressing uncertainty about the use of temperature in the problem.
  • Some participants question the calculations and suggest that the temperature is relevant for determining the speed of sound, which is necessary for the second part of the problem.
  • Others clarify that there are two time periods to consider: the time for the stone to hit the bottom and the time for the sound to travel back up.

Discussion Status

The discussion is ongoing, with participants exploring the need to combine the two time periods for a complete answer. There is no explicit consensus, but guidance has been provided regarding the relevance of temperature and the speed of sound.

Contextual Notes

Participants are navigating the implications of the problem setup, particularly regarding the use of temperature and the assumptions about sound travel in the context of the can's depth.

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Homework Statement


a man dropped a stone into a can that is 120m deep. if the temperature of the air is 20degree celsius. how long would it take for a man to hear the sound when the stone hit the can?

Homework Equations



d=Vi*t + 1/2*a*t^2


The Attempt at a Solution


since i know that the initial velocity is 0.0m/s
i canceled out the part vi*t
and solved for time ----> t= \sqrt{}2(d)/a
which is t= \sqrt{}2(120m)/9.81m/s^2= 7.2s

is this correct.? I am having a doubt on my answer because i didnt use the temperature at all.
 
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I'm not sure how you got 7.2s from that equation - maybe you entered in incorrectly into your calculator?

And the temperature is really only used as a reference in regards to the speed of sound. So, you have the time it takes the stone to hit the bottom of the can, and then the time for the sound to travel back to the man.
 
p21bass said:
I'm not sure how you got 7.2s from that equation - maybe you entered in incorrectly into your calculator?

And the temperature is really only used as a reference in regards to the speed of sound. So, you have the time it takes the stone to hit the bottom of the can, and then the time for the sound to travel back to the man.

wait. sorry i got wrong number from the calculator but the equation is right.right?
and also so are you saying that i had to use the temperature. and find thae speed of the time and add it with the time i got from the kinematic equation or just what i did was the end?
 
p21bass said:
I'm not sure how you got 7.2s from that equation - maybe you entered in incorrectly into your calculator?

And the temperature is really only used as a reference in regards to the speed of sound. So, you have the time it takes the stone to hit the bottom of the can, and then the time for the sound to travel back to the man.

Unless, of course, the man hears the sound that travels up through the walls of the can first! :wink:

That's a *big* can!
 
gneill said:
Unless, of course, the man hears the sound that travels up through the walls of the can first! :wink:

That's a *big* can!

what? wait. I am still confused so you mean the equation i did was the end. or i had to do add the time i got using the temperature?
 
There are two time periods involved. The first (which you've already addressed) is the time it takes for the stone to reach the bottom of the can. The second period is the time it takes for the sound from the impact to travel back up to the man. This second period involves the speed of sound in air which is temperature dependent (but not by too much unless the temperatures get really far from room temp). Simply look up the speed of sound at that temperature.
 
gneill said:
There are two time periods involved. The first (which you've already addressed) is the time it takes for the stone to reach the bottom of the can. The second period is the time it takes for the sound from the impact to travel back up to the man. This second period involves the speed of sound in air which is temperature dependent (but not by too much unless the temperatures get really far from room temp). Simply look up the speed of sound at that temperature.

no!so that means in the end you were supposed to add both of the times and that is your final answer? cause this question was on my test i stopped at the kinematic equation.
 
Yes, that's how that problem is solved.
 
p21bass said:
Yes, that's how that problem is solved.

ah man..at lest i did the half correctly . thank you so much for help! it was a great help!
 

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