Sound coming out of slide whistle

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SUMMARY

The discussion centers on calculating the length of a slide whistle required to play a note one octave higher than its original length of 27 cm. The correct approach involves understanding that the wavelength is inversely related to frequency; thus, to achieve a higher note, the whistle's length must be halved. The final conclusion is that the length of the whistle should be 13.5 cm, not meters, as the original measurement was in centimeters.

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A slide whistle has a length of 27 cm. if you want ot play a note one octave higher the whistle should be how long?


Ans : 1/2 lambda = L

there Lambda = 2L
= (2)(27)
= 54 m

is that correct?
 
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That's a rather long whistle.
And the higher the frequency, the shorter the wavelength, so the whistle should be shorter if it's to produce a higher note.
 
so it would be 27/2 = 13.5 m?

thanks
 
13.5 m is also a tad long for a whistle. It'll look more like a digderidoo.
The length of the slide whistle was given in cm, not in meters.
I assume the whistle acts like a half open tube where waves have a node on the closed end and have a maximum at the open end, then the whistle should be half as long.
 
jai6638 said:
so it would be 27/2 = 13.5 m?

thanks

What, exactly, was the original length of the whistle? (Be Careful!)
 
my bad.. so the answer is (.27)(2) = .54m?
 
Except that you are going the wrong way again: a longer wave length gives a lower frequency.

Since the original length was given as "27 cm.", I would be inclined to give the answer as 13.5 cm.
 

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