Sound Intensity Peak: Find Time Between Peaks

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SUMMARY

The discussion centers on calculating the time interval between peaks in sound intensity caused by two wheels rotating at different speeds: 850 RPM and 780 RPM. The beat frequency, determined by the difference in frequencies (70 RPM or 1.167 Hz), leads to a time period of approximately 0.85 seconds between successive peaks. The calculations involve converting RPM to Hz and applying the formula T = 1/f to find the time period. Constructive interference plays a crucial role in understanding the peaks in sound intensity.

PREREQUISITES
  • Understanding of sound wave interference and constructive interference
  • Knowledge of frequency conversion from RPM to Hz
  • Familiarity with the formula for wavelength (λ = Vs/f)
  • Basic mathematical skills for calculating beat frequency and time period
NEXT STEPS
  • Learn about sound wave interference patterns and their effects on sound intensity
  • Study the concept of beat frequency in acoustics
  • Explore the mathematical derivation of sound wave equations
  • Investigate practical applications of sound intensity in engineering and acoustics
USEFUL FOR

Students in physics, acoustics researchers, sound engineers, and anyone interested in the principles of sound wave interference and its applications.

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Homework Statement



One wheel goes at 850 rpm and the other at 780 rpm, and obviously they make a noise. Standing in an enclosed room, you hear the sound intensity increase and then decrease periodically due to wave interference. How long does it take between successive times for the sound intensity to reach a peak?


f1= 850
f2= 780
Vs =343 m/s

Homework Equations



λ=Vs/f

The Attempt at a Solution



343/850=0.40
343/780=0.44

So how do I find a peak? Does it have something to do with constructive interference?
 
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Yes.
 
What do you mean yes... What method would I use to find the peak between successive times?
 
I mean yes it's to do with constructive interference.

If you were to draw two sin waves to scale you would find they would go in and out of sync due to the difference in frequency. A peak on one won't always coincide with the peak of the other. When it does the result will sound louder. It's easy to see this when the frequencies are a multiple of each other...

http://hyperphysics.phy-astr.gsu.edu/hbase/sound/beat.html
 
Is there an equation to combine the two frequencies?
 
See that link I posted..

The beat frequency is equal to the absolute value of the difference in frequency of the two waves

but note the question askes for a time not a frequency.
 
So am I suppose to find the beat frequency of the two waves then determine the time?

E.g. 850-780=70RPM

T=1/f = 0.014s

Or do I have to convert the RPM to Hz and then find time?

70RPM=1.167Hz

T=0.856898s
 
Last edited:
What do you think? What are the units of Frequency? Work out the two frequencies first.
 
I guess frequency then. Why would I need to workout the two frequencies first? Wouldn't finding the difference and converting be faster?
 
  • #10
You could do that but the thing to remember is that the beat frequency is the difference between the two frequencies. Other problems may not make any reference to rpm.

So in summary.. They produce two tones, one at 14.17Hz and 13Hz. The beat frequency is the difference or 14.17-13 = 1.17Hz (Which is the answer you got). The time period between successive peaks in sound intensity is therefore 1/1.17 = 0.85seconds.
 
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