Spacecraft Acceleration Question

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SUMMARY

The discussion revolves around calculating the acceleration components of a spacecraft with initial velocity components of 4370 m/s (x-direction) and 6280 m/s (y-direction) while its engines are firing for 684 seconds. The displacement during this time is given as 4.11 x 10^6 m (x-direction) and 6.07 x 10^6 m (y-direction). The correct acceleration values derived from the equations of motion are 17.6 m/s² for the x-component and 25.9 m/s² for the y-component, which differ from the incorrect intermediate calculation of 4.79 m/s². The discussion emphasizes the importance of correctly applying the kinematic equation D = Vo*t + 1/2 at² to solve for acceleration.

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Lokhtar
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Homework Statement



On a spacecraft , two engines are turned on for 684s at a moment when the velocity of the craft has x and y components of Vox=4370 m/s and Voy = 6280 m/s. When the engines are firing, the craft undergoes a displacement that has components of x= 4.11x10^6m and y = 6.07x10^6m. Find the x and y components of the craft's acceleration.


Homework Equations



D = Vo*t + 1/2 at^2

The Attempt at a Solution



For X:
4.11*10^6m = 4370m(684s) + 1/2 a(684s)^2 = 4.79m/s^2

For Y:
6.07*10^6m = 6280m(684s) + 1/2 a(684s)^2 = 7.56m/s^2

The answers given are 17.6m/s^2 and 25.9m/s^2, but I am not sure why. I'd appreciate any help.
 
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Lokhtar said:
For X:
4.11*10^6m = 4370m(684s) + 1/2 a(684s)^2 = 4.79m/s^2

What is this "= 4.79m/s^2" all about? You're saying that

4.11*10^6m = 4.79m/s^2

which is false. The units don't even match.

Just solve the equation for "a". (And forget the 4.79m/s^2 part).

p.s. you probably know this, but the 4370m should have different units.
 

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