Special Functions: Complete Answers?

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SUMMARY

The discussion centers on the completeness of answers involving special functions, particularly the Gamma function and its relation to integrals. The integral ##\displaystyle \int_0^{\frac{\pi}{2}} \sqrt{\sin x} ~ dx = \frac{\sqrt{\pi} ~\Gamma (\frac{3}{4})}{2 \Gamma (\frac{5}{4})}## is presented as a case study. Participants debate whether expressing results in terms of the Gamma function or logarithmic functions provides a complete answer, given that these functions can also be evaluated numerically. The conclusion emphasizes that the utility of the result depends on the context, with numerical values favored by engineers and functional expressions preferred by theoretical physicists and mathematicians.

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  • Understanding of integral calculus, specifically definite integrals.
  • Familiarity with special functions, particularly the Gamma function.
  • Knowledge of numerical methods for evaluating integrals.
  • Basic concepts of mathematical analysis and function completeness.
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  • Explore the properties and applications of the Gamma function in mathematical analysis.
  • Learn numerical integration techniques for evaluating complex integrals.
  • Investigate the role of special functions in engineering applications.
  • Study the relationship between theoretical and numerical approaches in mathematics.
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Mathematicians, theoretical physicists, engineers, and students interested in the applications of special functions and numerical methods in calculus.

Mr Davis 97
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I have a relatively light question about special functions. As an example, it can be shown that ##\displaystyle \int_0^{\frac{\pi}{2}} \sqrt{\sin x} ~ dx = \frac{\sqrt{\pi} ~\Gamma (\frac{3}{4})}{2 \Gamma (\frac{5}{4})}##. Generally, the expression on the right would be taken as "the answer" to this problem. My question is, to what extent is this a complete answer? Isn't the gamma function technically just another integral that we don't know the value of? And if we derive the values of gamma numerically, why don't we just numerically evaluate the original integral to begin with?
 
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Mr Davis 97 said:
My question is, to what extent is this a complete answer?
The same is true for results expressed in e.g. ##\log## or ##\cos##. To what extend is that a complete answer?
Isn't the gamma function technically just another integral that we don't know the value of?
And the same hols true for ##\log##. Most values can only be given numerically, so why should we look for anti-derivatives at all?

This entire question depends heavily on what you will allow as fundamental function and what not. We know a lot of values of the Gamma function and many calculation rules, too. So given a result expressed in terms of the Gamma function can be used for further treatment - usually better than the original integral. In the end it always comes down to the question: What do you want to do with the result? A numerical value is certainly better for engineers, whereas the Gamma function might be better for theoretical physicists and mathematicians.
 
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