Special relativity question with lots of frames

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Homework Help Overview

The problem involves a scenario in special relativity where convicts escape from a planet in a spaceship, and a patrol ship pursues them. The speeds of the ships and a missile are given, and the task is to determine the time experienced by the pilot of the patrol ship when the missile strikes.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the interpretation of the speeds provided, questioning whether they are 'proper' speeds or relative to a specific frame. There is an exploration of how to apply relativistic velocity addition and the implications of relative simultaneity. Some participants express uncertainty about the need for distances in their calculations.

Discussion Status

The discussion is ongoing, with participants offering insights into the interpretation of the problem and suggesting approaches to calculate the missile's speed relative to the patrol ship. There is a recognition of the need to clarify the frames of reference and the nature of the velocities involved.

Contextual Notes

Participants note that the problem's wording regarding the convicts noticing the patrol ship may lead to different interpretations. There is also a mention of the need to track events in a single frame rather than considering multiple frames simultaneously.

Kara386
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Homework Statement


At exactly 00:00:00 hours, a group of convicts escape from a planet in a space-ship that travels at speed
##v=\frac{4}{5}c##.
After 11 min, a patrol spaceship goes after them with ##v_P=\frac{24}{25}c##.
Ignore all acceleration periods.
(i) The convicts immediately notice the patrol spaceship taking off, and release a stealth missile to destroy it. The missile has speed
##v_M=\frac{40}{41}c##
with respect to the convicts. Show that, when the missile hits the patrol ship, the time on a watch worn by the pilot of the patrol ship is 00 : 23 : 36.

Homework Equations


##u_x' = \frac{u_x-v}{1-\frac{u_xv}{c^2}}## (1)
##t' = \gamma (t - \frac{vx}{c^2})## (2)

The Attempt at a Solution


I should say this is from a past paper, so it won't get marked. There are way too many frames! I'm going to assume that all the speeds given are 'proper' speeds.

##u_x=\frac{40}{41}##, I think v is the speed of one frame relative to the other so that might be ##\frac{24}{25}-(-\frac{40}{41}) = \frac{1984}{1025}##. Then I realized that ##u_x'## might not be useful anyway, I was going to just use speed = distance/time, but can't do that because I don't know distances. And (2) probably isn't useful either. Do I try and work out at what time in the ship's frame the missile hits, and transform that? But then do I need to transform the 40/41 to see what the missile's speed is in the ship's frame? Don't I need distances for this approach as well?
 
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Kara386 said:
I'm going to assume that all the speeds given are 'proper' speeds.
There is no such thing. It is very well stated in the problem what the speeds are relative to.

What is not clear from the problem is what this means:
Kara386 said:
The convicts immediately notice the patrol spaceship taking off,
Now, there is only one physically sound interpretation of this, but I am not sure that this is what the problem writer intended.

Also, you do not need to consider more than one frame, you simply need to track what happens in one frame and possibly use concepts of relative simultaneity and so on.
 
Orodruin said:
There is no such thing. It is very well stated in the problem what the speeds are relative to.

What is not clear from the problem is what this means:

Now, there is only one physically sound interpretation of this, but I am not sure that this is what the problem writer intended.

Also, you do not need to consider more than one frame, you simply need to track what happens in one frame and possibly use concepts of relative simultaneity and so on.
Oops, didn't read it properly, clearly. All speeds relative to the planet. OK, I'll try sticking to the frame of the planet. I thought proper times, length etc were in the rest frame of an object?
 
No, all velocities are not given in the planet rest frame, but the velocities in the planet rest frame can be easily figured out using relativistic velocity addition.

Kara386 said:
I thought proper times, length etc were in the rest frame of an object?
Yes, but these are invariant quantities. There is no meaningful way of defining a proper velocity. If you take the velocity of an object in its rest frame it is zero by definition of the rest frame.
 
Orodruin said:
No, all velocities are not given in the planet rest frame, but the velocities in the planet rest frame can be easily figured out using relativistic velocity addition.Yes, but these are invariant quantities. There is no meaningful way of defining a proper velocity. If you take the velocity of an object in its rest frame it is zero by definition of the rest frame.
OK. So are the convict ship and spaceship velocities given in the planet's rest frame then? Just the missile one that isn't? If not I really don't understand the question.
 
My suggestion would be to calculate the speed of the missile relative to the patrol ship -
at what speed does the patrol ship see the approaching missile?
Then you would need the distance between the two ships after 11 minutes -
this would be relativistically contracted when the patrol ship takes off (you know how far the convict's ship
has traveled relative to earth).
Now if you have this information, speed and distance you should be able
to calculate the time for the missile to reach the patrol ship.
 
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