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alexmahone

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- Thread starter alexmahone
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- #1

alexmahone

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- #2

HallsofIvy

Science Advisor

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If you are asked to do a problem for a class, someone clearly expects that you know and can use a formula for this problem. And we have a right to expect that you

- #3

alexmahone

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If you are asked to do a problem for a class, someone clearly expects that you know and can use a formula for this problem. And we have a right to expect that youhaveread the forum rules and know you must make an attempt to solve the problem yourself and post that attempt here. We cannot give hints if we do not know exactly where you had a problem.

I get the answer 0.135c whereas my textbook says 0.385c. I was just hoping that someone could confirm that my answer is right. I didn't post my solution because I didn't want others to be biased by it.

- #4

alexmahone

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Let S be Tatooine and S' be the pursuit ship. Let P be the cruiser.

[tex]v=0.6c[/tex] [tex]u=0.8c[/tex]

[tex]v'=\frac{v-u}{1-uv/c^2}[/tex]

[tex]=\frac{0.6c-0.8c}{1-0.8c*0.6c/c^2}[/tex]

[tex]=-0.385c[/tex]

Is that correct?

[tex]v=0.6c[/tex] [tex]u=0.8c[/tex]

[tex]v'=\frac{v-u}{1-uv/c^2}[/tex]

[tex]=\frac{0.6c-0.8c}{1-0.8c*0.6c/c^2}[/tex]

[tex]=-0.385c[/tex]

Is that correct?

Last edited:

- #5

Doc Al

Mentor

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You made a sign error in the denominator.[tex]=\frac{0.6c-0.8c}{1+0.8c*0.6c/c^2}[/tex]

- #6

alexmahone

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You made a sign error in the denominator.

Oops; thanks.

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