- #1

Lucille

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## Homework Statement

bob and anna are in two space ships of proper length 100m; anna's ship passes bob's and is moving in the -x dir at v=0.75c. the front of anna's ship and the tail of bob's ship coincide at x=x'=t=t'=0. bob sits at the window in his ship and sees a clock inside anna's ship

a) what position is the window in bob's space ship

b) what time does this clock in anna's ship read

## Homework Equations

x'=gamma(x-vt)

x=gamma(x'+vt')

t'=gamma(-v/c^2*x+t)

t=gamma(v?c^2*x+t')

delta t = gamma delta to

L = Lo/gamma

## The Attempt at a Solution

a)

so if bob sees the clock at the end of anna's ship, then:

L=Lo/gamma = sqrt(1-v^2/c^2)*Lo = sqrt(1-0.75^2)*(100)=66.1m <-- position of bob's window in his space ship (distance from the end of his spaceship to the window)

b)

i tried :

x=100m

v=0.75c

t'=x'/v = 4.45 * 10^-7 s

But I'm not sure if this is correct...