What is the Relationship Between Specific Gravity and Dilution?

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SUMMARY

The discussion centers on the relationship between specific gravity (SG) and dilution, specifically in the context of a sodium hydroxide (NaOH) solution. Participants emphasize the importance of converting the problem into a mathematical expression involving mass fractions rather than molalities or molarities. A practical example provided involves calculating the weight of 200 ml of NaOH with an SG of 1.32, breaking it down into grams of water and NaOH. This approach simplifies the dilution process and aids in understanding the necessary calculations.

PREREQUISITES
  • Understanding of specific gravity (SG) and its implications in solution chemistry.
  • Basic knowledge of mass fractions and their application in dilution calculations.
  • Familiarity with sodium hydroxide (NaOH) properties and behavior in solutions.
  • Ability to perform unit conversions and algebraic manipulations in chemistry.
NEXT STEPS
  • Research the concept of mass fractions in solution chemistry.
  • Learn how to calculate specific gravity for various solutions.
  • Explore dilution calculations involving NaOH and other common laboratory reagents.
  • Study the differences between molality, molarity, and mass fraction in chemical solutions.
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in preparing chemical solutions and understanding dilution principles.

serendipityfox
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Homework Statement
how many grams of water to dilute 200ml noah (SG 1.32, 28.83%) to solution SG 1.157, 13.55%
Relevant Equations
sg= density x / density h20
i am nonplussed about how to proceed with this dilution, probably it is very simple.
 
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Hellp fox, :welcome: !

Work out your homework equation to turn this into a simple math problem and you'll be fine.
To do this, write a scenario, something like
200 ml NaOH of SG 1.32 weighs .. grams and consists of ... gram of H2O plus ... grams of NaOH
etc.
Then convert that into an expression in terms of symbols (not numbers) for the amount of water you need to add.
 
ok! thanks
 
Here you are dealing with mass fractions, not molalities and certainly not molarities !
 
i must think about this a little more...
 

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