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Specific heat and latent heat of fusion

  1. Dec 3, 2007 #1
    Hi this is my first post and I'm stumped on my last HW problem, so I'm open to suggestions or solutions.

    1. A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 35°C. In an attempt to cool the liquid, which has a mass of 220 g, 112 g of ice at 0.0°C is added. At the time at which the temperature of the tea is 15°C, determine the mass of the remaining ice in the jar. Assume the specific heat capacity of the tea to be that of pure liquid water.


    2. specific heat of water 4186 J/Kg*C
    Latent heat of fusion for water 3.33*10^5 J/Kg

    4186 Cp*.22 Kg*20 C=18418.4
    18418.4/3.33*10^5 Lf = .5531

    Why do I get more than i started with?
  2. jcsd
  3. Dec 3, 2007 #2
    please reply within the next 9.5 hours thanks :)
  4. May 3, 2008 #3


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    rahndezvous, don't forget that once you've melted the ice, you then need to increase the temperature of the melted ice to 15oC.
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