Hi this is my first post and I'm stumped on my last HW problem, so I'm open to suggestions or solutions.(adsbygoogle = window.adsbygoogle || []).push({});

1. A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 35°C. In an attempt to cool the liquid, which has a mass of 220 g, 112 g of ice at 0.0°C is added. At the time at which the temperature of the tea is 15°C, determine the mass of the remaining ice in the jar. Assume the specific heat capacity of the tea to be that of pure liquid water.

_______grams

2. specific heat of water 4186 J/Kg*C

Latent heat of fusion for water 3.33*10^5 J/Kg

Q=Cp*m*/\T

Q=m*Lf

m=Q/Lf

4186 Cp*.22 Kg*20 C=18418.4

18418.4/3.33*10^5 Lf = .5531

.5531*1000=553.1g

Why do I get more than i started with?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Specific heat and latent heat of fusion

**Physics Forums | Science Articles, Homework Help, Discussion**