Hi this is my first post and I'm stumped on my last HW problem, so I'm open to suggestions or solutions. 1. A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 35°C. In an attempt to cool the liquid, which has a mass of 220 g, 112 g of ice at 0.0°C is added. At the time at which the temperature of the tea is 15°C, determine the mass of the remaining ice in the jar. Assume the specific heat capacity of the tea to be that of pure liquid water. _______grams 2. specific heat of water 4186 J/Kg*C Latent heat of fusion for water 3.33*10^5 J/Kg Q=Cp*m*/\T Q=m*Lf m=Q/Lf 4186 Cp*.22 Kg*20 C=18418.4 18418.4/3.33*10^5 Lf = .5531 .5531*1000=553.1g Why do I get more than i started with?