(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

http://www.physics.ox.ac.uk/olympiad/Downloads/PastPapers/BPhO_PC_2006_QP.pdf

Q15b

Answers:

http://www.physics.ox.ac.uk/olympiad/Downloads/PastPapers/BPhO_PC_2006_MS.pdf

I am confused on how the answer is reached, specifically how the formula energy needed=power/rate of reduction is laid out

2. Relevant equations

energy needed = power/rate of reduction

3. The attempt at a solution

What I am confused about is that since power is in J/s and rate of reduction is in kg/s that would make Energy needed into J/kg... or specific heat capacity and not energy itself.

How does this work?

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# Homework Help: Specific Heat Capacity and Energy

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