Specific Heat Capacity and Energy

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SUMMARY

The discussion centers on the formula for calculating energy needed in relation to power and rate of reduction, specifically in the context of physics problems involving specific heat capacity. The formula presented is energy needed = power/rate of reduction, where power is measured in joules per second (J/s) and rate of reduction in kilograms per second (kg/s). The confusion arises from the interpretation of the units, which initially seem to suggest a conversion to specific heat capacity (J/kg). However, it is clarified that when the rate of reduction is 1 kg, the resulting unit simplifies to joules (J).

PREREQUISITES
  • Understanding of basic physics concepts, particularly energy and power.
  • Familiarity with units of measurement in physics, specifically joules and kilograms.
  • Knowledge of specific heat capacity and its relevance in thermodynamics.
  • Ability to interpret and manipulate equations involving energy calculations.
NEXT STEPS
  • Study the principles of specific heat capacity and its calculations in thermodynamics.
  • Learn about unit conversions in physics, particularly between energy, power, and mass.
  • Explore practical applications of the energy needed formula in real-world scenarios.
  • Review past physics Olympiad problems to enhance problem-solving skills in energy-related questions.
USEFUL FOR

Students studying physics, particularly those preparing for competitive exams like the Physics Olympiad, as well as educators teaching thermodynamics and energy concepts.

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Homework Statement



http://www.physics.ox.ac.uk/olympiad/Downloads/PastPapers/BPhO_PC_2006_QP.pdf

Q15b

Answers:
http://www.physics.ox.ac.uk/olympiad/Downloads/PastPapers/BPhO_PC_2006_MS.pdf

I am confused on how the answer is reached, specifically how the formula energy needed=power/rate of reduction is laid out

Homework Equations



energy needed = power/rate of reduction

The Attempt at a Solution



What I am confused about is that since power is in J/s and rate of reduction is in kg/s that would make Energy needed into J/kg... or specific heat capacity and not energy itself.

How does this work?
 
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Nevermind I realized that since the kg is 1, j/kg gives joules anyway
 

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