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Specific Heat Capacity and Energy

  1. Mar 6, 2012 #1
    1. The problem statement, all variables and given/known data

    http://www.physics.ox.ac.uk/olympiad/Downloads/PastPapers/BPhO_PC_2006_QP.pdf

    Q15b

    Answers:
    http://www.physics.ox.ac.uk/olympiad/Downloads/PastPapers/BPhO_PC_2006_MS.pdf

    I am confused on how the answer is reached, specifically how the formula energy needed=power/rate of reduction is laid out

    2. Relevant equations

    energy needed = power/rate of reduction

    3. The attempt at a solution

    What I am confused about is that since power is in J/s and rate of reduction is in kg/s that would make Energy needed into J/kg... or specific heat capacity and not energy itself.

    How does this work?
     
  2. jcsd
  3. Mar 7, 2012 #2
    Nevermind I realised that since the kg is 1, j/kg gives joules anyway
     
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