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## Homework Statement

A 4.80 kg piece of solid material is heated from 16.4C to 219C (3 s.f.) using 787 kJ of energy (3 s.f.).

Assuming an efficiency of 0.383 for the heating process, and that the material does not melt, calculate the specific heat capacity of the material.

## Homework Equations

Q=mc(Change in T)

## The Attempt at a Solution

c=Q/ m (Delta T)

=(787e3)/ (4.80 x 202.6)

= 809.2711418 k/kg/K

However they have given me a efficiency of 0.383? Do i just time that by my answer? We haven't been taught about efficiency.

Thank you