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Specific heat capacity - heat energy transfer

  1. Aug 20, 2014 #1
    1. The problem statement, all variables and given/known data

    Find the mass of water that vaporizes when 3.39 kg of mercury at 243 °C is added to 0.476 kg of water at 90.0 °

    2. Relevant equations
    q=mcT, q=mL


    3. The attempt at a solution
    When vaporising T=100degC. Heat lost by mercury = heat gained by water. 3.39kg x 139J/kg/C x (243-100) = 0.476kg x 4186J/kg/C x (100-10) + 22.6x10^5 J/kg x m
    m= 2.1 x 10^-5kg is what I get which is the wrong answer. Where have I gone wrong?
     
  2. jcsd
  3. Aug 20, 2014 #2
    Where did the 100-10 come from?

    Chet
     
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