Specific heat capacity - heat energy transfer

[slaw155]

Homework Statement

Find the mass of water that vaporizes when 3.39 kg of mercury at 243 °C is added to 0.476 kg of water at 90.0 °

Homework Equations

q=mcT, q=mL

The Attempt at a Solution

When vaporising T=100degC. Heat lost by mercury = heat gained by water. 3.39kg x 139J/kg/C x (243-100) = 0.476kg x 4186J/kg/C x (100-10) + 22.6x10^5 J/kg x m
m= 2.1 x 10^-5kg is what I get which is the wrong answer. Where have I gone wrong?

 

[Chestermiller]

Where did the 100-10 come from?

Chet