Specific volume and enthelpy of mercury

Click For Summary
The discussion revolves around determining the specific volume and enthalpy of mercury at 0.4 MPa and 55% quality, with the original poster seeking guidance after being away from thermodynamics. There is uncertainty regarding the existence of property tables for mercury, similar to steam tables for water, which complicates the problem-solving process. Suggestions include using available graphs and equations, such as the ideal gas law or Van der Waals equation, to find the specific volume and enthalpy. The conversation highlights the challenge of locating reliable resources for mercury's thermodynamic properties. Overall, participants are seeking clarification and direction on how to approach the problem effectively.
jahanzebikram
Messages
12
Reaction score
1
Homework Statement
"Determine the specific volume and enthalpy of mercury at 0.4 MPa and 55% quality."
Relevant Equations
Q = m c dT
I have been away from thermodynamics for a while, and there is a young mechanical engineering student who asked my help in solving the question. For the life of me I am unable to solve this problem and I am at my wit's end.

I believe I can solve the problem if some pointers are provided. Also, do property tables (like steam tables) for mercury exist?
If nothing else, then can I be directed towards the relevant study material? Any help is much appreciated.
 
Physics news on Phys.org
Google "Mercury thermodynamic properties"
 
jahanzebikram said:
Homework Statement:: "Determine the specific volume and enthalpy of mercury at 0.4 MPa and 55% quality."
Relevant Equations:: Q = m c dT

I have been away from thermodynamics for a while, and there is a young mechanical engineering student who asked my help in solving the question. For the life of me I am unable to solve this problem and I am at my wit's end.

I believe I can solve the problem if some pointers are provided. Also, do property tables (like steam tables) for mercury exist?
If nothing else, then can I be directed towards the relevant study material? Any help is much appreciated.
Well, I don't know if this helps (because I can't find "Satutrated Mercury Tables (liquid - vapor)", But let's pretend they do exist and it's just a matter of finding them.

To just refresh on the mechanics of that process: What do you get for the enthalpy of Saturated Water @ 4 Bar, 50% Quality?
 
erobz said:
Well, I don't know if this helps (because I can't find "Satutrated Mercury Tables (liquid - vapor)", But let's pretend they do exist and it's just a matter of finding them.

To just refresh on the mechanics of that process: What do you get for the enthalpy of Saturated Water @ 4 Bar, 50% Quality?
If I am not mistaken the enthalpy of Saturated water @ the given properties should be determined like this:

@ 4 bar
hf = 604.68 kJ/kg
hg = 2737.63 kJ/kg

so at x = 0.5

h = (1-x)hf + (x)hg
h = (0.5)604.68 + (0.5)2737.63
h = 1671.155 kJ/kg

but after a lot of googling, I have been unable to find saturated mercury tables so maybe there is some different way of finding out the solution that I don't have any idea about. Like I said, I have been away from thermodynamics for a while, and this question seemed like something I should be able to solve but can neither find head nor tails of it.
 
Chestermiller said:
Google "Mercury thermodynamic properties"
After being unable to hone the powers of "lord google", I turn to you to get me out of this sticky problem.
 
No expert, but a few thoughts about finding the specific volume.

Presumably we take 0.4MPa (about 4 atm) to be the vapour pressure. In this case, the system’s temperature can be read-off this graph:
https://i.stack.imgur.com/StSNl.gif

The graph is Figure 1 from this pdf document: https://www.physics.rutgers.edu/~eandrei/389/NISTIR.6643.pdf

We now know the temperature and pressure of the vapour and we can find its specific volume (e.g. maybe using the ideal gas equation, else Van der Waals equation with the appropriate constants for mercury).

We can easily find the specific volume for the liquid phase. So the overall specific volume can be determined.

Not sure if that is what’s intended though. Seems a bit convoluted!

And if I’ve misunderstood something, I’m sure someone can correct me.
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
6K
Replies
5
Views
5K