Speed at which to hurl a projectile?

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SUMMARY

The discussion centers on calculating the initial velocity of a stone hurled by Archimedes' catapult, which weighs 77 kg and travels 180 m. The initial velocity is determined to be greater than 42 m/s, assuming an optimal launch angle of 45 degrees for maximum range. The mass of the stone is deemed irrelevant due to the neglect of wind resistance. The conversation highlights the importance of understanding projectile motion equations, specifically the horizontal and vertical motion components.

PREREQUISITES
  • Understanding of projectile motion equations, specifically y = v_y0 t - (1/2) g t^2 and x = v_x0 t
  • Knowledge of the concept of optimal launch angles in projectile motion
  • Familiarity with basic physics principles, including gravity and motion
  • Ability to apply mathematical reasoning to solve physics problems
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  • Study the principles of projectile motion in detail, focusing on optimal angles and range calculations
  • Learn how to derive initial velocity using kinematic equations in physics
  • Explore the effects of varying launch angles on projectile distance and velocity
  • Investigate real-world applications of catapults and their physics in engineering contexts
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Students studying physics, educators teaching projectile motion concepts, and anyone interested in the mechanics of historical siege engines like catapults.

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Homework Statement


The Archimedes' catapult could hurl a 77 kg stone a distance of 180 m. What was the stone's initial velocity as it left the catapult? The wind resistance is assumed to be insignificant.


Homework Equations


y = v_y0 t - (1/2) g t^2
x = v_x0 t

The Attempt at a Solution


I think the mass of the stone is irrelevant as wind resistance is not taken into account. The problem would be easy if I knew the angle at which the catapult was fired. Here, however, both the angle and the initial velocity of the projectile are unknown. The answer provided by the textbook says the velocity is > 42 m/s. So clearly the 42 m/s is the initial velocity at the optimal angle and if you change the angle, you have to make up for it by launching at a greater initial velocity. I think the solution might have something to do with a derivative function, but other than that, I'm completely lost.
 
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There is an optimal angle, which gives the maximum range for a projectile launched from ground level. Perhaps your book has a discussion of "range" in the section on projectile motion?
 
Thanks. I figured it out now. So apparently the optimal angle is always 45 degrees.
 
Yes. Glad it worked out.
 

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