Speed from a distance vs. time graph

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SUMMARY

The discussion focuses on calculating maximum instantaneous speed from a distance vs. time graph. The user correctly identifies that velocity is determined by the formula velocity = distance/time, and notes that the steepest gradient occurs between 1 and 1.5 seconds, yielding a velocity of 80 cm per second. However, the user is advised to refine their approach by examining smaller time intervals to accurately estimate maximum instantaneous speed, as this method provides a more precise measurement of steepness on the graph.

PREREQUISITES
  • Understanding of basic kinematics, specifically velocity calculations.
  • Familiarity with graph interpretation, particularly distance vs. time graphs.
  • Knowledge of calculus concepts, specifically limits and instantaneous rates of change.
  • Ability to analyze gradients and slopes on a graph.
NEXT STEPS
  • Study the concept of limits in calculus to understand instantaneous speed.
  • Learn about the derivative as a tool for finding maximum speeds on curves.
  • Practice analyzing distance vs. time graphs with varying intervals.
  • Explore numerical methods for estimating derivatives from discrete data points.
USEFUL FOR

Students studying physics or mathematics, educators teaching kinematics, and anyone interested in understanding the relationship between distance, time, and speed in graphical form.

ravsterphysics
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Homework Statement


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Homework Equations

The Attempt at a Solution


I know velocity = distance/time and the steepest gradient means the maximum speed, and the gradient is steepest between 1 and 1.5 seconds with the change in distance being around 40cm so velocity = 40cm/0.5 = 80 cm per second.

So my answers are nowhere near what they want.

Where am I going wrong?
 

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You want an estimate of the maximum instantaneous speed. You might need to "zoom in" to a much smaller interval of time where the graph is steepest.
 
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