Speed of Rocket at 60 Degrees Elevation

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Discussion Overview

The discussion revolves around determining the speed of a rocket rising at a 60-degree angle of elevation from an observer located 100 meters away. Participants explore the relationship between the angle of elevation, the height of the rocket, and the rate of change of these quantities, involving both calculus and trigonometric relationships.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant notes the angle of elevation is increasing at 12 degrees per second when the angle is 60 degrees.
  • Another participant proposes that the height of the rocket can be calculated using trigonometric functions, suggesting a height of 173.21 meters based on the cosine of 60 degrees.
  • A different participant questions whether the speed of the rocket is 4800 m/sec.
  • Another participant calculates a speed of 83.73 m/s and emphasizes the need to find the rate of change of the rocket's height, \(\frac{dy}{dt}\), and to relate it to the angle of elevation using calculus.

Areas of Agreement / Disagreement

Participants express differing calculations for the speed of the rocket, with no consensus on the correct value. Multiple competing views on the approach to solving the problem remain evident.

Contextual Notes

Participants mention the need to convert degrees to radians for calculus applications, indicating potential limitations in the assumptions or methods used in their calculations.

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A rocket is rising vertically from a point on the ground 100 meters from an observer at ground level. The observer notes that the angle of elevation is increasing at a rate of 12 degrees per second when the angle of elevation is 60 degrees.

Find the speed of the rocket at that instant.
 
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Since we know the cos(60) =1/2 and the length is 100 meters, the hypothesis is 200 meters. The height then 200sin(60) = 173.21 meters. This problem then can be done with the calculus and can be done without using it. Remember to change degrees into radians for the calculus.
 
do u get 4800 m/sec?
 
I got 83.73 m/s

What do we want to figure out? The rate at which the rocket's height is changing, right? We want to find \frac{dy}{dt}.

We know:

\frac{d\theta}{dt}|_{\theta=\frac{\pi}{3}} = \frac{\pi}{15}

Solving using calculus you want to find an equation the relates the height to degrees with the given information, then find another equation that relates theta and the height with respect to time.
 
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