Speed of Sound in Air Problem- Is this correct?

[leehana10]

The speed of sound at 0°C in open air is 331.3 m/sec. At what temperature would the wavelength of a 440 Hz sound wave be 0.82 meters?

Equation to find the speed of sound: Vт = Vo √(T/273)

T = 273 + t(°C)

My calculations:

Vт = 440 Hz (0.82 m) = 360.8 m/s

Vт = Vo √(T/273)
360.8 m/s = 331.3 m/s (t^2)
-331.3 m/s = -331.3 m/s (t^2)
29.5 = t^2
√(29.5) = t
5.431 = t

 

[supratim1]

360.8 m/s = 331.3 m/s (t^2)
-331.3 m/s = -331.3 m/s (t^2)

How did you get that?

 

[leehana10]

Nvm. I got help from a friend. Thank you for your help though!

 

[supratim1]

welcome!