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**[SOLVED] speed of two protons (I think an easy question)**

## Homework Statement

If you release two protons from rest 1.500nm apart, calculate the top speed, relative to you, that either proton will achieve.

## Homework Equations

F=ma

ke^2/r=mv^2 where k=9.0e9 Nm^2/C^2 and e is the charge

## The Attempt at a Solution

mass proton = 1.67e-27

charge proton = 1.60e-19

So just plug in and solve for v=

v= [(9e9)((1.6e-19)^2/(1.5e-19))/1.67e-27]^1/2

v=9.59e3 m/s

I just wanted to make sure the process I used for this problem was correct...

Thanks!