Speed of two protons (I think an easy question)

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The discussion focuses on calculating the top speed of two protons released from rest at a distance of 1.500 nm apart. Using the formula derived from Coulomb's law and Newton's second law, the calculated speed is 9.59 x 10^3 m/s. The key variables involved include the mass of a proton (1.67 x 10^-27 kg) and the charge of a proton (1.60 x 10^-19 C). The solution process was confirmed as correct, with a minor correction regarding the distance used in the calculation.

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[SOLVED] speed of two protons (I think an easy question)

Homework Statement



If you release two protons from rest 1.500nm apart, calculate the top speed, relative to you, that either proton will achieve.

Homework Equations



F=ma

ke^2/r=mv^2 where k=9.0e9 Nm^2/C^2 and e is the charge

The Attempt at a Solution



mass proton = 1.67e-27
charge proton = 1.60e-19

So just plug in and solve for v=

v= [(9e9)((1.6e-19)^2/(1.5e-19))/1.67e-27]^1/2

v=9.59e3 m/s

I just wanted to make sure the process I used for this problem was correct...

Thanks!
 
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Looks good.

Just one typo ( r = 1.5e-19 ? ), but you did use the right number in the calculation.
 

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