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ilovejava

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## Homework Statement

In a proton linear accelerator, protons are accelerated to have a kinetic energy of 530 MeV. What is the speed of these protons? (The rest mass of a proton is 1.67

**×**10-27 kg.)

## Homework Equations

E

_{0}=m

_{0}c^2

E=E

_{0}/√1-(v^2)/(c^2)

E = KE + E

_{0}

## The Attempt at a Solution

Recognize that 1eV = 1.602E-19 Joules and 1MeV = 10E6 eV. I converted 530MeV to joules and it turned out to be 8.49E-11. I found the total energy using E = KE + E

_{0}to be 2.35E-10. I then solved for velocity using E=E

_{0}/√1-(v^2)/(c^2) and it turned out to be 2.306E8 C

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