Sphere Charge Hanging on Thread (Electric Field Question)

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HarleyM
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Homework Statement


Charge 1 (0.15 kg) in the following diagram is hanging from a light insulating thread, as shown in diagram (red is what I have added myself)
Free-body diagram of a hanging sphere on a thread at 40 degrees from vertical, with force components labelled Ft Sin 40 and Ft Cos 40, and a second sphere 0.4 m to the right.

Charge 2 is brought close and pulls charge 1 , deflecting the string away from the vertical axis by 40 degrees. The charges have the same magnitude, charge 1 is negative.

A) Find the tension in the thread
B) Find the charge on 2.

Homework Equations


Fg=mg
Fe=Kq2/r2


The Attempt at a Solution



Vertical

Fnet=0
0=FtCos40 + (-mg)
Ft=mg/cos40
Ft=1.92

Horizontal

Fnet=0
0=Fe+(-Ftsin40)
0=kq2/r2+(-1.92sin40)
q=√(1.92sin40)(0.42)/(9x109)
q=+/- 4.7x10-6C

How does this look?

Free-body diagram of sphere 1 hanging from a thread at 40 degrees from vertical, with tension components Ftsin40 and Ftcos40, weight -Fg downward, electric force Fe to the right toward charge 2, and a 0.4 m separation label.
 
Is there anything about that which concerns you?
How could you work out for yourself if you got the right answer?

FWIW: without crunching the numbers, your reasoning looks sound.
Comment the actual paper you hand in.
 
the answer q=+/- 4.7x10-6 C is not correct. Read the problem again. It says
The charges have the same magnitude, charge 1 is negative.

Do the charges attract or repel? What is charge 2 then?

ehild
 
Well I wrote +/- because it was a square root, the charge is actually positive I know because it attracts charge 1

Thank you for the input however I feel more confident with my physics knowledge everyday !
 
HarleyM said:
Well I wrote +/- because it was a square root, the charge is actually positive I know because it attracts charge 1

Then it was correct but it was not the solution yet.

HarleyM said:
Thank you for the input however I feel more confident with my physics knowledge everyday !

It was a nice solution. I especially liked the picture. You can be confident in your knowledge! :smile:

ehild
 
It is common for the math to give a choice of solutions - you pick the one that makes sense in terms of the physics.