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## Homework Statement

A particle that movies in three dimensions is trapped in a deep spherically symmetric potential V(r):

V(r) = 0 at r < r[itex]_{}0[/itex]

--> ∞ at r ≥ r[itex]_{}0[/itex]

where r[itex]_{}0[/itex] is a positive constant. The ground state wave function is spherically symmetric, so the radial wave function u(r) satisfies the one-dimensional Schroedinger energy eigenvalue equation (6.17) with the boundary condition u(0) = 0 (eq. 6.18).

Using the known boundary conditions on the radial wave function u(r) at r = 0 and r = r[itex]_{}0[/itex], find the ground state energy of the particle in this potential well.

## Homework Equations

6.17

-[itex]\hbar^{2}/2m[/itex] [itex]d^{2}/dr^{2}[/itex]u(r) + V(r)u(r) = Eu(r)

6.18

u(r) = rψ(r)

## The Attempt at a Solution

I know that there is no potential V(r) to deal with, since it is zero inside the well and infinite outside.

I also know that ψ is zero at r[itex]_{}0[/itex] and finite at zero.

So, that leaves me with finding a solution to

-[itex]\hbar^{2}/2m[/itex] [itex]d^{2}/dr^{2}[/itex]u(r) = Eu(r)

which I am a bit confounded with. Even then, how do I go from a solution to that to finding the ground state energy?

Thanks.